Phy 231
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion:
Answer: Fnet = m * a, Fnet = 12kg * 3m/s^2 = 36N
• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion:
Answer: a = Fnet / m = 20N / 4kg = 5m/s^2.
• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion:
Answer: a = F / m = 20N / 10kg = 2m/s^2. The object is actually accelerating at 1.5m/s^2 so obviously there’s other forces acting on the object or the object would have an acceleration of 2m/s^2.
• What is the total of all those forces and in what direction does this total act?
answer/question/discussion:
Answer: F = m*a = 10kg * .5m/s^2 = 5N. There is a 20N force acting on the object in the direction of motion and a 5N force acting on the object against the objects motion. The total force is 25N.
The net force is 1.5 m/s^2 * 10 kg = 15 N, not 25 N.
This is to be understood as the resultant of the 20 N force you exert in one direction and the 5 N force exerted in the opposite direction by the other forces.
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15 minutes
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