course Phy 241 If the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 20 cm/s2) / clip, and if the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 47 clips / unit of ramp slope, then how many cm/s2 of acceleration should correspond to 1 unit of ramp slope? If 52 clips are necessary to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the acceleration of the cart?If there are 20 cm/s^2 per 1 paper clip and for 47 paper clips there is one unit of ramp slope we can use a ratio to find that an acceleration of 940, (47*20) cm/s^2, is equivalent to one unit of ramp slope. We can use a ratio again to have 20 cm/s^2/1 paper clip=x acceleration /52 paper clips to equal 1040 cm/s^2.