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Phy 201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
At slope 0.05:
‘ds = 10m
‘dt = 8s
V0 = 0
vAve = 1.25m/s
vf = 2.5m/s
a = 0.3125m/s^2
At slope 0.1:
‘ds = 10m
‘dt = 5s
V0 = 0
vAve = 2m/s
vf = 4m/s
a = 0.8m/s^2
The acceleration increased by 0.4875m/s^2 when slope increased by .05
So the acceleration increases by 0.4875m/s^2 for every .05 increase in slope, or 0.4875 / .05 = 9.75m/s^2 for every 1 increase in slope.
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