#$&*
Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Copy the problem below into a text editor or word processor.
• This form accepts only text so a text editor such as Notepad is fine.
• You might prefer for your own reasons to use a word processor (for example the formatting features might help you organize your answer and explanations), but note that formatting will be lost when you submit your work through the form.
• If you use a word processor avoid using special characters or symbols, which would require more of your time to create and will not be represented correctly by the form.
• As you will see within the first few assignments, there is an easily-learned keyboard-based shorthand that doesn't look quite as pretty as word-processor symbols, but which gets the job done much more efficiently.
You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
________________________________________
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
5kg * 9.8m/s^2 = 49N
6kg * 9.8m/s^2 = 58.8N
The direction of acceleration will go towards the heavier weight.
Fnet = -49 + 58.8 = 9.8N
9.8N / 11kg = 0.89m/s^2
#$&*
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 1.8m/s
vf = ?
‘dt = 1s
‘ds = ?
a = -0.89m/s^2
Assuming the initial direction of motion is going with the 5kg mass, 1.8m/s will be positive, and acceleration will be negative.
Vf = 1.8m/s -0.89m/s
Vf = 0.91m/s
The object will be moving at 0.91m/s, still in the original direction of motion. (it has not yet reached 0 velocity and reversed)
#$&*
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
The velocity after one second is in the same direction of motion, the acceleration is in the opposite direction of motion. The system is slowing down.
#$&*
&#Very good responses. Let me know if you have questions. &#