course Mth 271 ¶ïoÓƒ|ƙ龨F£û}½³“wѽýû¡åÓ¦|¹Óassignment #008
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15:27:40 What functions f(z) and g(t) express the function 2^(3t-5) as a composite f(g(t))?
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RESPONSE --> f(t) = 2^t g(t) = 3t - 5 confidence assessment: 2
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15:27:59 CORRECT STUDENT RESPONSE: f(z)=2^z and g(t)=3t-5, so that f(g(t)) = 2^g(t) = 2^(3t-5).
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RESPONSE --> self critique assessment: 3
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15:32:40 1.3.81 (was 1.3.66 temperature conversion. What linear equation relates Celsius to Fahrenheit?
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RESPONSE --> I found the slope of the line (212 - 32) / (100 - 0) = 180/100 = 9/5. One of the given points contains the y intercept since C is 0 when F is 32. Writing the equation is slope-intercept form y = mx + b, I get the equation C = (9/5)F + 32 confidence assessment: 3
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15:33:00 CORRECT STUDENT RESPONSE: degrees Fahrenheit=1.8(degrees Celsius)+32, or F = 1.8 C + 32. INSTRUCTOR COMMENT: Since each Fahrenheit degree is 1.8 Celsius degrees a graph of F vs. C will have slope 1.8. Since F = 32 when C = 0 the graph will have vertical intercept at (0, 32) so the y = m x + b form will be F = 1.8 C + 32.
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RESPONSE --> self critique assessment: 3
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15:34:29 How did you use the boiling and freezing point temperatures to get your relationship?
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RESPONSE --> The boiling and freezing point relationships of C and F were like data points for values x and y. I found the slope by taking (F2 - F1) / (C2 - C1) confidence assessment: 3
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15:34:49 A graph of Fahrenheit vs. Celsius temperatures gives us the two (x,y) points (o,32) and (100,212). We use these two points to find the slope m=(y2-y1)/(x2-x1) = (212 - 32) / 100 = 1.8. Now we insert the coordinates of the point (0,32) and into the point-slope form y = 1.8 x + b of a line to get 32 = 1.8 * 0 + b. We easily solve to get b = 32. {So the equation is y = 1.8 x + 32, or F = 1.8 C + 32. **
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RESPONSE --> self critique assessment: 3
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