Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
The vector travels into the third quadrant.
answer/question/discussion:
Question on the rotating the x-y coordinate plane. Aren't we just drawing a vector at 250 degrees from the standard x-y axes which is just left ot the 270 degree vertical?
What are the x and y components of the equilibrant of the force?
sin 250 deg = -.94: y = -.94 * 10 N = -9.4 N = y component
cos 250 deg = -.34: x = -.34 * 10 N = -3.4 N = x component
answer/question/discussion:
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15 minutes
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Looks good.