#$&*
PHY 201
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_03.1_labelMessages.txt **
Samantha Rogers
PHY 201
Seed 2.3
The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
• What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
vAve = `ds / `dt
vAve = 30 cm / 5 sec
vAve = 6cm/sec
#$&*
• If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
vf = 2 * vAve
vf = 2 * 6cm/sec
final velocity = 12cm/sec
#$&*
• By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The velocity of the ball therefore changed by a total of 12cm/sec.
`dv = vf - v0
`dv = 12cm/sec - 0cm/sec
`dv = 12cm/sec
#$&*
• At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
aAve = `dv / `dt
aAve = (12cm/sec) / (5sec)
aAve = 2.4cm/sec^2
#$&*
• What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Acceleration doesn't change, therefore it is uniform.
The slope of the graph is constant.
It is a straight line that rises from v= 0 to v=30 while the x-axis (clock time) changes by 5 seconds.
#$&*
*#&!
&#Your work looks very good. Let me know if you have any questions. &#