#$&*
PHY 201
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_04.1_labelMessages **
Samantha Rogers
PHY 201
Seed 4.1
The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The graph has velocity of the y axis and clock time on the x axis. It is a straight line that is representing acceleration.
#$&*
Sketch a straight line segment between these points.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This line represents acceleration of the ball.
#$&*
@&
The line represents velocity vs. clock time.
As you have already demonstrated, you know that the slope of the line represents the acceleration.
*@
What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rise is 30cm/s
The run is 5 sec
The slope is 30cm/sec / 5 sec = 6cm/sec^2
#$&*
What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The area of the graph beneath this segment would be the area of the trapezoid.
(10cm/s + 40cm/s) / 2 = (50cm/sec) / 2 = 25cm/s
25cm/s * 5 sec = 25cm
area is 25 cm.
#$&*
*#&!
@&
25 * 5 = 125, not 25.
Otherwise great.
*@