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PHY 201
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** CQ_1_08.1_labelMessages **
Samantha Rogers
PHY 201
Seed 8.1
A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 25m/s
a = -10m/s^2
`dt = 1sec
vf = 25m/s + -10m/s^2 * 1 sec
vf = 15m/s
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• What will be its velocity at the end of two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vf = 25m/s + -10m/s^2 * 2 sec
vf = 5m/s
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• During the first two seconds, what therefore is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 25m/s
vf = 5m/s
vAve = (25m/s + 5m/s) /2 = 15m/s
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• How far does it therefore rise in the first two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = `ds / `dt
15m/s = `ds / 2s
`ds = 30m
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• What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf = 25m/s + -10m/s^2 * 3 sec
vf = -5m/s
vf = 25m/s + -10m/s^2 * 4 sec
vf = -15m/s
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• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: ->->->->->->->->->->->-> :
Reaches maximum when it comes to rest, which is at 2.5 seconds.
vf = 25m/s + -10m/s^2 * 2.5 sec
vf = 0m/s
(25m/s + 0m/s) / 2 = 12.5m/s
12.5m/s = `ds / 2.5s
`ds = 21.25m
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• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf = 25m/s + -10m/s^2 * 4 sec
vf = -15m/s
vAve = (-15m/s + 25m/s) / 2 = 5m/s
5m/s = `ds / 4s
`ds = 20 meters
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• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf = 25m/s + -10m/s^2 * 6 sec
vf = -35m/s
vAve = (-35m/s + 25m/s) / 2 = -5m/s
-5m/s = `ds / 6s
`ds = -30 meters
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*#&!
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