#$&*
PHY 201
Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_09.1_labelMessages **
Samantha Rogers
PHY 201
Seed 9.1
A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds.
• What are its average velocity, final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
`ds = 20cm
v0 = 0cm/s
`dt = 2s
vAve = 20cm/2s = 10cm/s
vf = 2(10cm/s) = 20cm/s
a = 20cm/s / 2s = 10cm/s^2
#$&*
• If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
`dt = 2 * .03 = .06 so, 2s + .06s = 2.06s
v0 = 0cm/s
`ds = 20cm
vAve = 20cm/2.06s = 9.71cm/s
vf = 2(9.71cm/s) = 19.42cm/s
a = 19.42cm/s / 2.06s = 9.42cm/s^2
#$&*
• What is the percent error in each?
answer/question/discussion: ->->->->->->->->->->->-> :
The percent error for time interval was 3%. The percent error final velocity was 3%. The percent error for acceleration was 6%.
#$&*
• If the percent error is the same for both velocity and acceleration, explain why this must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
the are not the same.
#$&*
• If the percent errors are different explain why it must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
To find the percent error in velocity you divided it by the interval. Then when calculating the percent error in acceleration we again divided by the time interval which gives us another 3% error, totally the percent error to 6%.
#$&*
** **
15 minutes
** **
6/14/2012 5:25
This looks very good. Let me know if you have any questions.