cq_1_111

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PHY 201

Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_11.1_labelMessages **

Samantha Rogers

PHY 201

Seed 11.1

Answer the following based on Newton's Second Law:

• How much net force is required to accelerate a 12 kg mass at 3 m/s^2? 

answer/question/discussion: ->->->->->->->->->->->-> :

 12 kg * 3m/s^2 = Fnet

Fnet = 36 Newtons

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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons? 

answer/question/discussion: ->->->->->->->->->->->-> :

 20N = 4 kg * a

20N / 4 kg = 5m/s^2

a = 5m/s^2

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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own? 

answer/question/discussion: ->->->->->->->->->->->-> :

 a = Fnet / m

a = 20N / 10 kg

a = 2 m/s^2

I know there are other forces acting on the object besides my own because the calculations show that the object should be moving at an acceleration of 2m/s^2. Since it is only moving at 1.5m/s^2, then there is an opposing force acting upon the object.

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• What is the total of all those forces and in what direction does this total act?

answer/question/discussion: ->->->->->->->->->->->-> :

 If I am pushing with a force of 20 N and the acceleration of the object is 1.5m/s^2, then we can figure out that the opposing force is -5N because

20N + (-5N) = 15N

Fnet = 15N

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