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PHY 201
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_19.2_labelMessages **
Samantha Rogers
PHY 201
Seed 19.2
Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
The force vector is still vertical. The force vector is along the negative vertical axis. Then rotated the coordinate system counterclockwise through an angle of 20 degrees, this means that the x axis is pointing in a 20 degree direction above horizontal. The y axis is 20 degrees to the 'left' of vertical.
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• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
The x and y components of a vector of magnitude 10 N, directed at 250 degrees are
x component : 10 N cos(250 deg) = -3N
y component : 10 N * sin(250 deg) = -9N
The x and y components of the equilibrate are equal and opposite to those of the force
x component of equilibrant: + 3 N
y component of equilibrant: +9 N
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&#Your work looks very good. Let me know if you have any questions. &#