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PHY 201
Your 'torques' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Torques_labelMessages **
7/1/2012 5:40
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Samantha Rogers
PHY 201
Torque Experiment
Disassemble the system, sketch the lines indicating the directions of the forces and the rod (as shown in the above figure). Make the measurements necessary to determine the length of each rubber band, and also measure the position on the rod at which each force is applied.
You can measure the position at which each force is applied with respect to any point on the rod. For example, you might measure positions from the left end of your horizontal line. In the above figure, for example, the B force might be applied at 3 cm from the left end of the line, the A force at 14 cm from the left end of the line, and the C force at 19 cm from the left end.
indicate the following:
In the first line, give the positions of the three points where the vertical lines intersect the horizontal line, in order from left to right.
In the second line give the lengths of the rubber band systems B, A and C, in that order.
In the third line give the forces, in Newtons, exerted by the rubber band systems, in the same order as before.
In the fourth line specify which point was used as reference point in reporting the three positions given in the first line. That is, those three positions were measured relative to some fixed reference point; what was the reference point?
Starting in the fifth line, explain how the forces, in Newtons, were obtained from your calibration graphs.
Beginning in the sixth line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> (note A doubled) intersections B A C, lengths B A C, forces B A C, reference point, how forces determined
******** ******** Your answer (start in the next line):1,7,12
8.75, 8.4, 8.3
1.9, 2.6, 1.3
The end point of the left side of the horizontal line
I corresponded the lengths with the rubber band to determine the corresponding force. If the length of the rubber band fell in between the lengths of the chart I averaged the corresponding forces to determine the force closer to that length.
The results indicate the lengths of the rubber bands and the forces associated with them
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Analyze results:
Vertical equilibrium: Determine whether the forces are in vertical equilibrium by adding the forces to obtain the net force, using + signs on upward forces and - signs on downward forces.
Give your result for the net force in the first line below.
In the second line, give your net force as a percent of the sum of the magnitudes of the forces of all three rubber band systems.
Beginning in the third line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> Fnet, Fnet % of sum(F)
******** Your answer (start in the next line):2.6- 1.3- 1.9= -.6
-10%
Obviously there was some discrepancy in my measurements because the net force should equal zero if the force are in vertical equilibrium. to figure out the percentage i calculated -.6 / 5.8 and then multiplied by 100
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Rotational equilibrium: We will regard the position of the central supporting hook (the hook for system A) to be the fulcrum around which the rod tends to rotate. Determine the distance from this fulcrum to the point of application of the force from rubber band B. This distance is called the moment-arm of that force. Do the same for the rubber band at C.
report the moment-arm for the force exerted by the rubber band system B, then the moment-arm for the system C. Beginning in the second line, briefly explain what the numbers mean and how you obtained them.
----->>>>>>>>
******** Your answer (start in the next line):5cm
7cm
This is the distance the downward forces are away from the upward force
#$&* moment arms for B, C
Make an accurate scale-model sketch of the forces acting on the rod, similar to the one below. Locate the points of application of your forces at the appropriate points on the rod. Use a scale of 4 cm to 1 Newton for your forces, and sketch the horizontal rod at its actual length.
Give in the first line the lengths in cm of the vectors representing the forces exerted by systems B, A and C, in that order, in comma-delimited format.
In the second line give the distances from the fulcrum to the points of application of the two 'downward' forces, giving the distance from the fulcrum to the point of application of force B then the distance from the fulcrum to the point of application of. force C in comma-delimited format, in the given order.
Beginning in the third line, briefly explain what the numbers mean and how you obtained them.
----->>>>>>>> (4 cm to 1 Newton scale) lengths of force vectors B, A, C, distances of B and C from fulcrum:
******** Your answer (start in the next line):7.6, 10.4, 5.2
5, 7
these are the lengths of the forces in 4cm to 1N scale and the distance frome the fulcrum to both downward forces
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The force from rubber band C will tend to rotate the rod in a clockwise direction. This force is therefore considered to produce a clockwise torque, or 'turning force', on the rubber band. A clockwise torque is considered to be negative; the clockwise direction is considered to be the negative direction and the counterclockwise direction to be positive.
When the force is exerted in a direction perpendicular to the rod, as is the case here, the torque is equal in magnitude to the product of the moment-arm and the force.
What is the torque of the force exerted by rubber band C about the point of suspension, i.e., about the point we have chosen for our fulcrum?
Find the torque produced by rubber band B about the point of suspension.
Report your torques , giving the torque produced by rubber band B then the torque produced by the rubber band C, in that order. Be sure to indicate whether each is positive (+) or negative (-). Beginning in the next line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> torque C, torque B
******** Your answer (start in the next line):-9.1
9.5
rubber band C would have a negative torque since the direction is clockwise so -7 *1.3 = -9.1 and rubber band b would have a positive torque since it is pulling in the counterclockwise direction so 1.9 * 5 = 9.5
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Ideally the sum of the torques should be zero. Due to experimental uncertainties and to errors in measurement it is unlikely that your result will actually give you zero net torque.
Express the calculated net torque--i.e, the sum of the torques you have found--as a percent of the sum of the magnitudes of these torques.
Give your calculated net torque in the first line below, your net torque as a percent of the sum of the magnitudes in the second line, and explain starting at the third line how you obtained this result. Beginning in the fourth line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> tau_net, and as % of sum(tau)
******** Your answer (start in the next line):.4
2.2%
9.5 + 9.1= 10.6 and .4/ 10.6= .0215 * 100= 2.2%
.4 is the net torque which ideally should be 0 but due to experimental error is .4 and the percentage would 2.2% of the sum of the magnitudes
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Physics 121 students may stop here. Phy 121 students are not required to do the remaining two parts of this experiment, but may do so if they wish.
Simulating Forces and Torques on a Bridge
The figure below represents a bridge extended between supports at its ends, represented by the small triangles, and supporting two arbitrary weights at arbitrary positions (i.e., the weights could be anything, and they could be at any location).
The weights of the objects act downward, as indicated by the red vectors in the figure. The supports at the ends of the bridge hold the bridge up by exerting upward forces, represented by the upward blue vectors.
If the bridge is in equilibrium, then two conditions must hold:
1. The total of the two upward forces will have the same magnitude as the total of the two downward forces. This is the conditional of translational equilibrium. That is, the bridge has no acceleration in either the upward or the downward direction.
2. The bridge has no angular acceleration about any axis. Specifically it doesn't rotate about the left end, it doesn't rotate about the right end, and it doesn't rotate about either of the masses.
Setup
We simulate a bridge with the setup indicated below. As in Part I the system is set up with the plywood square, and with a 1-cm grid on top of the plywood.
The threaded rod will be supported (i.e., prevented from moving toward the bottom of the board) by two push pins, and two stretched rubber bands will apply forces analogous to the gravitational forces on two weights supported by the bridge.
Stretch one rubber band to the length at which it supported 8 dominoes in the calibration experiment, and call this rubber band B. Stretch the other to the length that supported 4 dominoes and call this rubber band C. Rubber band C should be twice as far from its end of the rod as rubber band B is from its end, approximately as shown below.
Use push pins (now shown) to fix the ends of the hooks and keep the rubber bands stretched.
Note that the length of the threaded rod might be greater than the width of the board, though this probably won't occur. If it does occur, it won't cause a serious problem--simply place the push pins as far as is easily feasible from the ends and allow a little overlap of the rod at both ends.
Be sure the rubber bands are both 'vertical'--running along the vertical lines of the grid. It should be clear that the push pins are each exerting a force toward the top of the board.
Place two more rubber bands, with the hooks at the positions of the push pins, as indicated below. Stretch these rubber bands out simultaneously until their combined forces and torques just barely begin to pull the rod away from the push pins supporting it. Fix push pins through the free-end hooks, so that the two new rubber bands support the rod just above the push pins supporting it, as close to the supporting pins as possible.
Remove the supporting pins. This should have no effect on the position of the rod, which should now be supported in its original position by the two new rubber bands.
Mark the ends of each of the four rubber bands, and also the position of the rod. Your marks should be sufficient to later construct the following picture:
Now pull down to increase the length of the rubber band C to the length at which that rubber band supported the weight of 10 dominoes, and use a push pin to fix its position.
This will cause the lengths of the rubber bands A, B and D to also change. The rod will now lie in a different position than before, probably at some nonzero angle with horizontal.
Mark the position of the rod and the positions of the ends of the four rubber bands, in a manner similar to that used in the previous picture. Be sure to distinguish these marks from those made before.
Analyze your results
The figure below indicates the first set of markings for the ends of the rubber bands, indicated by dots, and the line along which the force of each rubber band acts. The position of the rod is indicated by the horizontal line. The force lines intersect the rod at points A, B, C and D, indicated by x's on the rod.
From your markings determine, for the first setup, the length of each rubber band and, using the appropriate calibration graphs or functions, find the force in Newtons exerted by each.
Sketch a diagram, to scale, depicting the force vectors acting on the rod. Use a scale of 1 N = 4 cm. Label each force with its magnitude in Newtons, as indicated in the figure. Also label for each force the distance along the rod to its point of application, as measured relative to the position of the leftmost force.
In the figure shown here the leftmost force would be the 2.4 N force; its distance from itself is 0 and isn't labeled. The 5 cm, 15 cm and 23 cm distances of the other forces from the leftmost force are labeled.
For the first setup (before pulling down to increase the force at C), give the forces, their distances from equilibrium and their torques, in comma-delimited format with one torque to a line. Give lines in the order A, B, C and D. Be sure your torques are positive if counterclockwise, negative if clockwise. Beginning in the following line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> (ABCD left to right, position wrt A) four forces, four dist, four torques
******** Your answer (start in the next line): 1.52,6.5, - 9.88
1.52, 5, 7.6
1.3, 7, 9.1
.76, 5, -3.8
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In the figure shown above the sum of all the vertical forces is 2.4 N + 2.0 N - 3.2 N - 1.6 N = 4.4 N - 4.8 N = -.4 N. Is this an accurate depiction of the forces that actually acted on the rod? Why or why not?
In the first line give the sum of all the vertical forces in your diagram. This is the resultant of all your forces.
In the second line, describe your picture and its meaning, and how well you think the picture depicts the actual system..
----->>>>>>>> (from scaled picture) sum of vert forces, describe picture and meaning
******** Your answer (start in the next line):
.54
my picture is very similar to the one above with two forces pulling upwards and two pulling downwards. in reality the sum of the forces should be 0 since the rod should be held up evenly, but due to experimental inaccuracies my answer is off.
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In the figure shown above the 1.6 N force produces a clockwise torque about the leftmost force (about position A), a torque of 1.6 N * 15 cm = 24 N cm. Being clockwise this torque is -24 N cm. The 2.0 N force at 23 cm produces a clockwise torque of 2.0 N * 23 cm = 26 N cm. Being counterclockwise this torque is +26 N cm.
In the first line below give the net torque produced by the forces as shown in this figure. Beginning in the second line describe your picture and discuss whether it could be an accurate depiction of torques actually acting on a stationary rod. Support your discussion with reasons.
----->>>>>>>> net torque from given picture, describe your picture
******** Your answer (start in the next line):
using the same process, i got the torques would be 0, 16, -24 and 46 so the net torque would be equal 38. this doesn't seem right though
take the distance of each force from the equilibrium position and multiply that by the force exert??
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Now calculate your result
What is the sum for your diagram of the torques about the point of action of the leftmost force (i.e., about position A)? This is your experimentally observed resultant torque about A. Give your result in the first line below.
For your diagram what is the magnitude of your resultant force and what is the sum of the magnitudes of all the forces acting on the rod? Give these results in the second line in comma-delimited format.
Give the magnitude of your resultant force as a percent of the sum of the magnitudes of all the forces. Give this result in the third line.
For your diagram what is the magnitude of your resultant torque and what is the sum of the magnitudes of all the torques acting on the rod? Give these two results, and the magnitude of your resultant torque as a percent of the sum of the magnitudes of all the torques, as three numbers in your comma-delimited fourth line.
Beginning in the fifth line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> sum(tau) about A, Fnet and sum(F), Fnet % of sum(F), | tau_net |, sum | tau |, |tau_net| % of sum|tau|
******** Your answer (start in the next line): im unclear about this step. is this calculation different from the equilibrium calculation or i have i gone wrong somewhere in the experiment??
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Perform a similar analysis for the second setup (in which you increased the pull at C) and give your results below:
For your diagram, what is the sum of the torques about the point of action of the leftmost force (i.e., about position A)? This is your experimentally observed resultant torque about A. Give your result in the first line below.
For your diagram what is the magnitude of your resultant force and what is the sum of the magnitudes of all the forces acting on the rod? Give these results in the second line in comma-delimited format.
Give the magnitude of your resultant force as a percent of the sum of the magnitudes of all the forces. Give this result in the third line.
For your diagram what is the magnitude of your resultant torque and what is the sum of the magnitudes of all the torques acting on the rod? Give these two results, and the magnitude of your resultant torque as a percent of the sum of the magnitudes of all the torques, as three numbers in your comma-delimited fourth line.
Beginning in the fifth line, briefly explain what your results mean and how you obtained them.
----->>>>>>>> (pull at C incr) sum(tau) about A, Fnet and sum(F), Fnet % of sum(F), | tau_net |, sum | tau |, |tau_net| % of sum|tau|
******** Your answer (start in the next line):
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For the second setup, the forces were clearly different, and the rod was not completely horizontal. The angles of the forces were therefore not all 90 degrees, though it is likely that they were all reasonably close to 90 degrees.
Look at your diagram for the second setup. You might want to quickly trace the lines of force and the line representing the rod onto a second sheet of paper so you can see clearly the directions of the forces relative to the rod.
In the first setup, the forces all acted in the vertical direction, while this may not be the case in this setup.
In the second setup, were the forces all parallel to one another? If not, by about how many degrees would you estimate they vary? Include a brief explanation of what your response means and how you made your estimates.
----->>>>>>>> (incr pull at C) variation of forces from parallel
******** Your answer (start in the next line): no the forces down were primarily parallel but the two upward ones were angled towards each other. they may have each strayed from the perpendicular by about 5 to 10 degrees
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Estimate the angles made by the lines of force with the rod in the second setup, and give your angles in comma-delimited format in the first line below. Your angles will all likely be close to 90 degrees, but they probably won't all be 90 degrees. The easiest way to estimate is to estimate the deviation from 90 degrees; e.g., if you estimate a deviation of 5 degrees then you would report an angle of 85 degrees. Recall that you estimated angles in the rotation of a strap experiment.
Starting in the second line give a short statement indicating how you made your estimates and how accurate you think your estimates were.
----->>>>>>>> angles of lines of force with rod
******** Your answer (start in the next line): 85, 80,90,90
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Your instructor is trying to gauge the typical time spent by students on these experiments. Please answer the following question as accurately as you can, understanding that your answer will be used only for the stated purpose and has no bearing on your grades:
Approximately how long did it take you to complete this experiment?
******** Your answer (start in the next line):
1 hour 45 minutes
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&#Your work on this lab exercise looks good. Let me know if you have any questions. &#