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PHY 201
Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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PHY 201
Seed 27.1
A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
• What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
weight = Fgrav = m * accel_grave = m g
weight = .4 kg * 9.8m/s^2 = 3.92 N
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• What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
3.92 N weight acts downward
2.5 N tension acts upward
2.5 - 3.92 N + Fbuoy = 0
Fbuoy = 1.42 N
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• What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> :
1000 kg / m^3
1000 kg / m^3 * 9.8 m/s^2 = 9800 N/m^3
V * 9800N/m^3 =1.42 N
V = 1.42 N / (9800N/m^3) = .000145 m^3
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• What is its density?
answer/question/discussion: ->->->->->->->->->->->-> :
D = m / v = 400 g / (145 cm^3) = 2.8 g / cm^3
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15 minutes
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7/10/2012 12:55
Very good responses. Let me know if you have questions.