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course Phy 121
10: 55 am June 15
An automobile rolls 10 meters down a constant incline with a slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.At what average rate is the automobile’s acceleration changing with respect to the slope of the incline?
Answer/question/discussion?
10 m/8 seconds= 1.25 m/s
Can assume that the initial velocity is 0 so the final velocity is 2.5 m/s (double 1.25)
= (2.5 m/s- 0)/8= .3125 m/s
10 m/ 5 sec= 2 sec
Initial is 0 (assumed) and the final would be double 2 (4m/sec)
= (4-0)/5= .8 m/seconds
(acceleration and slope)
(.8-.3125)(.10-.05)= 9.75 m/second (average rate of change of acceleration slope of the line)
Took about 20 min"
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