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course Phy 121
10:30 am June 15
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds. Based on this information what is its acceleration?
answer/question/discussion:
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Find initial velocity
2 meters= vAve * .64
=3.125
Final velocity, plug this number back into the equation.
VAve= (v0 + vf)/ 2
= 3.125 * 2= 6.25 m/sec
Acceleration
(6.25) * (6.25)= 2a + a
39.06/4 a= about 9.77 m/sec ^2
Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion:
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Was pretty close to the 9.8 m/s^2
Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion:
Yes
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&#Very good responses. Let me know if you have questions. &#