Orientation

course Mth 174

end program??????????????

assignment #001

001. Only assignment: prelim asst

qa prelim

......!!!!!!!!...................................

18:35:23

01-14-2009 18:35:23

`q001. Part 1 includes six activities. If you have completed an activity, just enter the answer 'completed'.

This question is appearing in the Question box. The box to the right is the Answer box, where you will type in your answers to the questions posed here.

To use this program you read a question, then enter your answer in the Answer box and click on Enter Answer. In your answers give what is requested, but don't go into excruciating detail. Try to give just enough that the instructor can tell that you understand an item.

After entering an answer click on Next Question/Answer above the Question box.

Do you understand these instructions?

......!!!!!!!!...................................

NOTES -------> Enter, as appropriate, an answer to the question, a critique of your answer in response to a given answer, your insights regarding the situation at this point, notes to yourself, or just an OK. OK

.......................................................!!!!!!!!...................................

18:39:19

01-14-2009 18:39:19

This program has created the folder c:\vhmthphy on your hard drive.

Browse to that folder and locate the file whose name begins with SEND. The name of this file will also include your name, as you gave it to the program, and the file will show as a Text file.

Never tamper with a SEND file in any way. It contains internal codes as if these codes are tampered with you won't get credit for the assignment. However you are welcome to copy this file to another location and view it, make changes, etc. Just be sure that when requested to do so you send the instructor the original, tamper-free file.

State in the Answer box whether or not you have been able to locate the SEND file. Don't send the SEND file yet. Note that more questions/instructions remain in the q_a_prelim.

......!!!!!!!!...................................

NOTES -------> I have located the SEND file.

.......................................................!!!!!!!!...................................

18:40:51

`q002. Note that every time you click on Enter Answer the program writes your response to your SEND file. Even if the program disappears all the information you have entered with the Enter Answer button will remain in that file. This program never 'unwrites' anything. Even if this program crashes your information will still be there in the SEND file. Explain this in your own words.

......!!!!!!!!...................................

RESPONSE -->

Every time I click on enter answer, the response is saved in the SEND file, and is never removed.

.................................................

......!!!!!!!!...................................

18:42:47

Any time the instructor does not post a response to your access site by the end of the following day, you should resubmit your work using the Submit Work form, and be sure at the beginning to indicate that you are resubmitting, and also indicate the date on which you originally submitted your work.

If you don't know where your access site is or how to access it, go to

http://www.vhcc.edu/dsmith/_vti_bin/shtml.dll/request_access_code.htm and request one now. You can submit the q_a_prelim without your access code, but other assignments should contain your code.

......!!!!!!!!...................................

RESPONSE -->

.................................................

......!!!!!!!!...................................

18:43:29

`q003. If you are working on a VHCC computer, it is probably set up in such a way as to return to its original configuration when it is rebooted. To avoid losing information it is suggested that you back up your work frequently, either by emailing yourself a copy or by using a key drive or other device. This is a good idea on any computer. Please indicate your understanding of this suggestion.

......!!!!!!!!...................................

RESPONSE -->

I need to back up all work.

.................................................

????{?R???????assignment #001

001. typewriter notation

qa initial problems

01-14-2009

......!!!!!!!!...................................

20:08:11

`q001. Explain the difference between x - 2 / x + 4 and (x - 2) / (x + 4). The evaluate each expression for x = 2.

......!!!!!!!!...................................

RESPONSE -->

x - 2 / x + 4 is different because it does not contain parentheses that would allow what is inside to be solved first. When evaluating these expression for x = 2, 2 is plugged into the x value, and the expression is solved. The one without parenthesis is 1/4 and the answer to the one with parenthesis is 0. The first equation allows for simplifying because it does not have parenthesis.

confidence assessment: 1

.................................................

......!!!!!!!!...................................

20:20:14

`q002. Explain the difference between 2 ^ x + 4 and 2 ^ (x + 4). Then evaluate each expression for x = 2.

Note that a ^ b means to raise a to the b power. This process is called exponentiation, and the ^ symbol is used on most calculators, and in most computer algebra systems, to represent exponentiation.

......!!!!!!!!...................................

RESPONSE -->

I miss calculated the first expression after putting x - 2 on top of x + 4. This confused me and I thought I could simplify the 2 and 4. After seeing the problem written across in one line, it becomes obvious how the order of operations is used. I tend to make easier problems much more difficult than they are. Understanding how to do this problem will help me to learn the best way to set up the problem and use order of operations.

confidence assessment:

.................................................

?}????w?U??€???

assignment #001

001. typewriter notation

qa initial problems

01-14-2009

......!!!!!!!!...................................

20:23:08

01-14-2009 20:23:08

The order of operations dictates that grouped expressions must be evaluated first, that exponentiation must be done before multiplication or division, which must be done before addition or subtraction.

It makes a big difference whether you subtract the 2 from the x or divide the -2 by 4 first. If there are no parentheses you have to divide before you subtract. Substituting 2 for x we get

2 - 2 / 2 + 4

= 2 - 1 + 4 (do multiplications and divisions before additions and subtractions)

= 5 (add and subtract in indicated order)

If there are parentheses you evaluate the grouped expressions first:

(x - 2) / (x - 4) = (2 - 2) / ( 4 - 2) = 0 / 2 = 0.

......!!!!!!!!...................................

NOTES -------> I miss calculated the first expression after putting x - 2 on top of x + 4. This confused me and I thought I could simplify the 2 and 4. After seeing the problem written across in one line, it becomes obvious how the order of operations is used. I tend to make easier problems much more difficult than they are. Understanding how to do this problem will help me to learn the best way to set up the problem and use order of operations.

.......................................................!!!!!!!!...................................

20:30:22

`q002. Explain the difference between 2 ^ x + 4 and 2 ^ (x + 4). Then evaluate each expression for x = 2.

Note that a ^ b means to raise a to the b power. This process is called exponentiation, and the ^ symbol is used on most calculators, and in most computer algebra systems, to represent exponentiation.

......!!!!!!!!...................................

RESPONSE -->

When parenthesis are added to the expression, the x + 4 must be calculated before evaluating anything else. Therefore, 2 ^ (x + 4) = 64 because 2 + 4 = 6 and 2 ^ 6 = 64, and 2 ^ 2 + 4 = 8 because the exponent is solved before addition.

confidence assessment: 2

.................................................

......!!!!!!!!...................................

20:31:50

01-14-2009 20:31:50

2 ^ x + 4 indicates that you are to raise 2 to the x power before adding the 4.

2 ^ (x + 4) indicates that you are to first evaluate x + 4, then raise 2 to this power.

If x = 2, then

2 ^ x + 4 = 2 ^ 2 + 4 = 2 * 2 + 4 = 4 + 4 = 8.

and

2 ^ (x + 4) = 2 ^ (2 + 4) = 2 ^ 6 = 2*2*2*2*2*2 = 64.

......!!!!!!!!...................................

NOTES -------> I understand how the order of operation applies to these problems because solving exponents comes before solving addition.

.......................................................!!!!!!!!...................................

20:45:03

`q003. What is the numerator of the fraction in the expression x - 3 / [ (2x-5)^2 * 3x + 1 ] - 2 + 7x? What is the denominator? What do you get when you evaluate the expression for x = 2?

......!!!!!!!!...................................

RESPONSE -->

The numerator is x - 3 and the denominator is

[ (2x -5)^3x + 1 ] - 2 + 7x. When evaluating the expression for x = 2 I used order of operations and did the following:

2 - 3 / [ (2(2) -5)^2 * 3(2) + 1} - 2 + 7(2),

-1/ [ (-1)^2 * 6 + 1] - 2 + 14,

-1/ [ 1 * 6 + 1] - 2 + 14,

-1/ [ 6 + 1] -2 + 14,

-1/ 7 - 2 + 14,

-1/7 + 12,

-1/ 19

confidence assessment: 2

.................................................

......!!!!!!!!...................................

20:56:00

The numerator is 3. x isn't part of the fraction. / indicates division, which must always precede subtraction. Only the 3 is divided by [ (2x-5)^2 * 3x + 1 ] and only [ (2x-5)^2 * 3x + 1 ] divides 3.

If we mean (x - 3) / [ (2x-5)^2 * 3x + 1 ] - 2 + 7x we have to write it that way.

The preceding comments show that the denominator is [ (2x-5)^2 * 3x + 1 ]

Evaluating the expression for x = 2:

- 3 / [ (2 * 2 - 5)^2 * 3(2) + 1 ] - 2 + 7*2 =

2 - 3 / [ (4 - 5)^2 * 6 + 1 ] - 2 + 14 = evaluate in parenthese; do multiplications outside parentheses

2 - 3 / [ (-1)^2 * 6 + 1 ] -2 + 14 = add inside parentheses

2 - 3 / [ 1 * 6 + 1 ] - 2 + 14 = exponentiate in bracketed term;

2 - 3 / 7 - 2 + 14 = evaluate in brackets

13 4/7 or 95/7 or about 13.57 add and subtract in order.

The details of the calculation 2 - 3 / 7 - 2 + 14:

Since multiplication precedes addition or subtraction the 3/7 must be done first, making 3/7 a fraction. Changing the order of the terms we have

2 - 2 + 14 - 3 / 7 = 14 - 3/7 = 98/7 - 3/7 = 95/7.

COMMON STUDENT QUESTION: ok, I dont understand why x isnt part of the fraction? And I dont understand why only the brackets are divided by 3..why not the rest of the equation?

INSTRUCTOR RESPONSE: Different situations give us different algebraic expressions; the situation dictates the form of the expression.

If the above expression was was written otherwise it would be a completely different expression and most likely give you a different result when you substitute.

If we intended the numerator to be x - 3 then the expression would be written (x - 3) / [(2x-5)^2 * 3x + 1 ] - 2 + 7x, with the x - 3 grouped.

If we intended the numerator to be the entire expression after the / the expression would be written x - 3 / [(2x-5)^2 * 3x + 1 - 2 + 7x ].

......!!!!!!!!...................................

RESPONSE -->

I understand now why the x isn't part of the numerator, and that it would be if there were parenthesis around it and the 3. This also explains why the -2 + 7x isn't part of the denominator.

self critique assessment: 2

.................................................

......!!!!!!!!...................................

21:07:51

`q004. Explain, step by step, how you evaluate the expression (x - 5) ^ 2x-1 + 3 / x-2 for x = 4.

......!!!!!!!!...................................

RESPONSE -->

step 1: substitute 4 for x

(4 - 5) ^2(4)-1 + 3/ 4-2

Step 2: solve parenthesis

(-1)^8-1 + 3/ 4-2

Step 3: solve exponent

(-1)^7=-1 so -1 + 3/4 -2

Step 4: solve addition and then subtraction

-1-2 + 3/4

-1-2.75

-3.75

confidence assessment: 1

.................................................

......!!!!!!!!...................................

21:12:25

We get

(4-5)^2 * 4 - 1 + 3 / 1 - 4

= (-1)^2 * 4 - 1 + 3 / 4 - 2 evaluating the term in parentheses

= 1 * 4 - 1 + 3 / 4 - 2 exponentiating (2 is the exponent, which is applied to -1 rather than multiplying the 2 by 4

= 4 - 1 + 3/4 - 2 noting that 3/4 is a fraction and adding and subtracting in order we get

= 1 3/4 = 7 /4 (Note that we could group the expression as 4 - 1 - 2 + 3/4 = 1 + 3/4 = 1 3/4 = 7/4).

COMMON ERROR:

(4 - 5) ^ 2*4 - 1 + 3 / 4 - 2 = -1 ^ 2*4 - 1 + 3 / 4-2 = -1 ^ 8 -1 + 3 / 4 - 2.

INSTRUCTOR COMMENTS:

There are two errors here. In the second step you can't multiply 2 * 4 because you have (-1)^2, which must be done first.?Exponentiation precedes multiplication. ?

Also it isn't quite correct to write -1^2*4 at the beginning of the second step. If you were supposed to multiply 2 * 4 the expression would be (-1)^(2 * 4).?

Note also that the -1 needs to be grouped because the entire expression (-1) is taken to the power.?-1^8 would be -1 because you would raise 1 to the power 8 before applying the - sign, which is effectively a multiplication by -1.?......!!!!!!!!...................................

RESPONSE -->

Again, it is extremely important to locate the parenthesis and understand how they apply. I made the same mistake of grouping numbers that should not be grouped because there is no parenthesis around them.

self critique assessment: 2

.................................................

......!!!!!!!!...................................

21:14:18

*&*& Standard mathematics notation is easier to see. On the other hand it's very important to understand order of operations, and students do get used to this way of doing it.

You should of course write everything out in standard notation when you work it on paper.

It is likely that you will at some point use a computer algebra system, and when you do you will have to enter expressions through a typewriter, so it is well worth the trouble to get used to this notation.

Indicate your understanding of the necessity to understand this notation.

......!!!!!!!!...................................

RESPONSE -->

It is important to understand notation from paper to the computer so that the correct procedure is used in solving problems.

self critique assessment: 2

.................................................

......!!!!!!!!...................................

21:20:56

`q005. At the link

http://www.vhcc.edu/dsmith/genInfo/introductory problems/typewriter_notation_examples_with_links.htm

(copy this path into the Address box of your Internet browser; alternatively use the path

http://vhmthphy.vhcc.edu/ > General Information > Startup and Orientation (either scroll to bottom of page or click on Links to Supplemental Sites) > typewriter notation examples

and you will find a page containing a number of additional exercises and/or examples of typewriter notation.Locate this site, click on a few of the links, and describe what you see there.

......!!!!!!!!...................................

RESPONSE -->

There are several practice problems that allow you to arrange the expression correctly and then look at the picture.

confidence assessment: 3

.................................................

......!!!!!!!!...................................

21:25:04

while students in other courses should understand the notation and should understand the more basic simplifications.

There is also a link to a page with pictures only, to provide the opportunity to translated standard notation into typewriter notation.

......!!!!!!!!...................................

RESPONSE -->

Understanding notation is extremely important to being able to work problems for this class.

self critique assessment: 2

.................................................

&#Good responses. Let me know if you have questions. &#