#$&* course Mth 173 2/15 2:16 AM
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Given Solution: This derivative will tell us the rate at which the volume changes with respect to the diameter of the pile. On a graph of the y = k x^3 curve the slope of the tangent line is equal to the derivative. Through the given point we can sketch a line with the calculated slope; this will be the tangent line. Knowing the slope and the change in x we easily find the corresponding rise of the tangent line, which is the approximate change in the y = k x^3 function. In short you use y' = 3 k x^2 to calculate the slope, which you combine with the change `dx in x to get a good estimate of the change `dy in y. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q Query class notes #08What equation do we get from the statement 'the rate of temperature change is proportional to the difference between the temperature and the 20 degree room temperature'? What sort of graph do we get from this equation and why? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: rates of change normally means a value altered by another value....I remember having difficulty with a quadratic and finding its rate of change. you said rate of change was 'dy/'dx so 'dy/'dx= ???this confuses me because of how similiar a bunch of things we do are...so is the derivative a rate as it approaches 0...and what about the differential...is it the average rate of change in y? and i remember at one point we used the second derivative... proportionality uses k.... so 'dy'dx=k and what what was the proportionality? T-20 so 'dy/'dx=k(T-20) well from looking at what values we would plug in, and the change being from a gap of temperature, as the Temperature gets closer to the gap value, 20, I say it would stop changing, so the graph would be decreasing at a decreasing rate confidence rating #$&*: 2 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: STUDENT SOLUTION AND INSTRUCTOR COMMENT: Would it be y = x-20 degrees., with y being the rate of temperature change and x being the temperature?You get a graph with a straight line and a slope of -20? INSTRUCTOR COMMENT: Not a bad attempt. However, you wouldn't use y to represent a rate, but rather dy /dt or y'. An in this example I'm going to use T for temperature, t for clock time. Read further. We need a graph of temperature vs. clock time, not rate of change of temperature vs. clock time. The difference between temperature and room temperature is indeed (T - 20). The rate of change of the temperature would be dT / dt. To say that these to our proportional is to say that dT / dt = k ( T - 20). To solve the situation we would need the proportionality constant k, just as with sandpiles and other examples you have encountered. Thus the relationship is dT / dt = k ( T - 20). Since dT / dt is the rate of change of T with respect to t, it tells you the slope of the graph of T vs. t. So the equation tells you that the slope of the graph is proportional to T - 20. Thus, for example, if T starts high, T - 20 will be a relatively large positive number. We might therefore expect k ( T - 20) to be a relatively large positive number, depending on what k is. For positive k this would give our graph a positive slope, and the temperature would move away from room temperature. If we are talking about something taken from the oven, this wouldn't happen--the temperature would move closer to room temperature. This could be accomplished using a negative value of k. As the temperature moves closer to room temperature, T - 20 becomes smaller, and the steepness of the graph will decrease--i.e., as temperature approaches room temperature, it will do so more and more slowly. So the graph approaches the T = 20 value more and more slowly, approaching as an asymptote. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q Query Inverse Functions and Logarithms, Problem 7. Construct table for the squaring function f(x) = x^2, using x values between 0 and 2 with a step of .5. Reverse the columns of this table to form a partial table for the inverse function. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: if f(x) is x^2, then g(x) would be sqrt(x) if it would be its inverse. the way to state inverse is f^-1(x). so x f(x) and f(x) f^-1(x) 0 0 0 0 .5 .25 .25 .5 1 1 1 1 1.5 2.25 2.25 1.5 2 4 4 2 confidence rating #$&*: 3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: STUDENT SOLUTION: We get the following ordered pairs: Table 1-- (0,0),(.5,.25),(1,1),(1.5,2.25),(2,4) Table2--(0,0),(.25,.5),(1,1),(2.25,1.5),(4,2). Plot the points corresponding to the table of the squaring function, and plot the points corresponding to the table of its inverse. Sketch a smooth curve corresponding to each function. The diagonal line on the graph is the line y = x. Connect each point on the graph of the squaring function to the corresponding point on the graph of its inverse function. How are these pairs of points positioned with respect to the y = x line? ** The segments connecting the graph points for function and for its inverse will cross the y = x line at a right angle, and the graph points for the function and for the inverse will lie and equal distances on either side of this line. The graph of the inverse is therefore a reflection of the graph of the original function through the line y = x. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q **** 8. If we reversed the columns of the 'complete' table of the squaring function from 0 to 12, precisely what table would we get? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 0-144 would be the complete table for the squaring function, and the reverse table would be 0-12. this includes all numbers, not just the integer values. confidence rating #$&*: 3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** We would get a table of the square root function with the first column running from 0 to 144, the second column consisting of the square roots of these numbers, which run from 0 to 12. ** Sketch the graphs of the functions described by both tables. 9. If we could construct the 'complete' table of the squaring function from 0 to infinity, listing all possible positive numbers in the x column, then why would we be certain that every possible positive number would appear exactly one time in the second column? &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q ** The table you constructed had only some of the possible x and y values. A complete table, which couldn't actually be written down but can to an extent be imagined, would contain all possible x values. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: This is true, you could chec every number you want. the decimals go on forever. and x is directly related to y, there is no adding and subtracting, simply y is x^2 confidence rating #$&*: 2 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: We could be sure because every number is the square of some other number. If the function was, for example, x / (x^2 + 1) there would be a great many positive numbers that wouldn't appear in the second column. But this is not the case for the squaring function. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique Rating: OK ********************************************* Question: `q What number would appear in the second column next to the number 4.31 in the first column? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: for a square function? x= 4.31 so f(x)= 4.31^2 or 18.5761. ???why must we mention them in first and second colums? the second colum is just f(x)=x^2, so what is the importance of mentioning it as second colum, instead of for f(x)=x^2 confidence rating #$&*: 3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** In the original table the second column would read 18.57, approx.. This is the square of 4.31. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q What number would appear in the second column next to the number `sqrt(18) in the first column? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: if the first column is f(x)=sqrt(18), depending if the second column is x, or f^-1(x) would change the answer, but for f^1(x) it would be 18^2 or 324. if just x then 18. Or then again if we are considering x=sqrt(18) then it would depend again if we are using f(x)=sqrt(x) or if f^-1(x)=x^2 if x=sqrt(18) then most likely we would be applying f^-1(x)=(sqrt(18))^2 or 18 confidence rating #$&*: 2 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** 18 would appear in the second column because the square of sqrt(18) is 18. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): It seems to me there are assumptions being made to the columns, its a little confusing for me when they aren't explicitly defined. ------------------------------------------------ Self-critique Rating:
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Given Solution: ** The number would be `pi^2 ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q What would we obtain if we reversed the columns of this table? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: In a literal approach you would have f(x)=x^2 in column one, and x in column two. But making the assumption column 1 will always be labeled x, and it is now pi^2, and column two will always be some function of x, and it has become pi, therefore taking the square root, column two now becomes f(x)=sqrt(x), or if we saved our original function, we would say it is the inverse, and it would be f^-1(x)=sqrt(x) all of x values now being x^2 basically confidence rating #$&*:3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: STUDENT ANSWER: We would obtain the inverse, the square roots of the squares being in the y colume and the squared numbers being in the x column. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q What number would appear in the second column next to the number 4.31 in the first column of this table? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: table being column one f(x)=x^2 and column 2 being f^-1(x)? 4.31 confidence rating #$&*:2 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: This number would be 4.31 squared,18.5761. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): would that not be the table for x f(x)=x^2, it sounded to me as if we were talking of f(x) and f^-1(x) ------------------------------------------------ Self-critique Rating:2 ********************************************* Question: `q What number would appear in the second column next to the number `pi^2 in the first column of this table? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: assuming column 1 is f(x)=x^2, and column two is f^-1(x) then pi confidence rating #$&*: 3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: STUDENT ANSWER: This number would be the square root, 'pi &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q What number would appear in the second column next to the number -3 in the first column of this table? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: assuming column 1 is x and column 2 is f(x)= x^2 then 9. if it is f^-1(x) then it is an imaginary number. confidence rating #$&*:3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: There is no such number. No real number has a square equal to -3, since the square of any number which is positive or negative is the product of two numbers of like sign and is therefore positive. Put another way: sqrt(-3) is not a real number, since the square of a real number cannot be negative. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: 13. Translate each of the following exponential equations into equations involving logarithms, and solve where possible: 2 ^ x = 18 2 ^ (4x) = 12 5 * 2^x = 52 2^(3x - 4) = 9. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 2^x=18 log2(18)=x = log(18)/log(2) which should equal 4 ???When I type it in, i get 4.1699..... is my program using natural instead of log, or something, it should be exactly 4 should it not?
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Given Solution: b^x = c is translated into logarithmic notation as log{base b}(c) = x. So: 2^x = 18 translates directly to log{base 2}(18) = x. For 5 * 2^x = 52, divide both sides by 5 to get 2^x = 10.4. Now take logs: x = log{base 2}(10.4) You can easily evaluate this and the preceding solution on your calculator. 2^(3x-4) = 9 translates to log{base 2}(9) = 3x - 4. Solving for x we get x = (log(base 2)(9) + 4) / 3. This can be evaluated using a calculator. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q 14. Solve 2^(3x-5) + 4 = 0 ** YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: not sure how to do this with logarithms if that is what you want, because we would want to move that 4 to the other side, which would then make us take the logarithm of it, which would not be possible, or rather be an imaginary number. but It does seem as x approaches negative infinity you get closer to your answer. confidence rating #$&*: 3 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: 2^(3x-5) + 4 = 0 rearranges to 2^(3x-5) =-4, which we translate as 3x-5 = log {base 2}(-4) = log(-4) / log (2). However log(-4) doesn't exist. When you invert the 10^x table you don't end up with any negative x values. So there is no solution to this problem. Be sure that you thoroughly understand the following rules: 10^x = b translates to x = log(b), where log is understood to be the base-10 log. e^x = b translates to x = ln(b), where ln is the natural log. a^x = b translates to x = log{base a} (b), where log{base a} would be written in your text as log with subscript a. log{base a}(b) = log(b) / log(a), where log is the base-10 log. It also works with the natural log: log{base a}(b) = ln(b) / ln(a). ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q Solve 2^(1/x) - 3 = 0 YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: 2^(1/x)=3 log2(3)=1/x 1.585=1/x 1.585x=1 x=.6309 ???I feel like most cases you wouldn't multiply by x.. confidence rating #$&*:1 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** Rearrange to 2^(1/x) = 3. Then take log of both sides: log(2^(1/x) ) = log(3). Use properties of logs: (1/x) log(2) = log(3). Solve for x: x = log(2) / log(3). ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): Not sure what was done different, but the answers come out the same...
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Given Solution: ** 2^x * 2^(1/x) = 15. By the laws of exponents we get 2^(x +1/x) = 15 so that x + 1/x = log {base2}(15) or x + 1/x =log(15) / log(2). Multiply both sides by x to get x^2 + 1 = [log(15) / log(2) ] * x. This is a quadratic equation. Rearrange to get x^2 - [ log(15) / log(2) ] * x + 1 = 0 or x^2 - 3.91 * x + 1 = 0. Solve using the quadratic fomula. ** Solve (2^x)^4 = 5 ** log( (2^x)^4 ) = log(5). Using laws of logarithms 4 log(2^x) = log(5) 4 * x log(2) = log(5) 4x = log(5) / log(2) etc.** STUDENT QUESTION Even with the solution I am missing a step as I work from x+(1/x)=log15/log2 to the final solution? INSTRUCTOR RESPONSE As stated, you multiply both sides of that equation by x. x * ( x + 1/x) = x^2 + 1, and multiplying the other side by x gives the obvious expression, so you get x^2 + 1 = [log(15) / log(2) ] * x &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK
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Given Solution: ** f(10,000) is the cost of 10,000 sq ft. f^-1(20,000) is the number of square feet you can cover for $20,000. ** STUDENT COMMENT Still not positive about the - 1. INSTRUCTOR RESPONSE f ^-1 (x) is the notation for the inverse function. If x is quantity A and f(x) is the value of quantity B, then when you invert the function x becomes quantity B and f ^-1 (x) becomes quantity A. In the original function x is the area and f(x) is the cost. When inverted to the form f ^-1 (x), x becomes the cost and f ^-1 (x) the area. You can think of inverting a function in terms of switching the columns of a table. We can also think of inverting a function in terms of switching the x and y coordinates on a graph, which reflects the graph through the line y = x. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q problem 1.3.38 4th edition (problem omitted from 5th edition but everyone should do this problem). Write an equation for the function if we vertically stretch y = x^2 by factor 2 then vertically shift the graph 1 unit upward. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: vertically stretching by a factor 2? exactly what does that mean? making the the rise go twice as fast? so 2x^2? and shift the graph 1 upward would be +1 so y=2x^2 + 1 confidence rating #$&*:2 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** Vertically stretching y = x^2 we get y = 2 x^2. The vertical shift adds 1 to all y values, giving us the function y = 2 x^2 + 1. ** STUDENT QUESTION I graphed the solution for vertically stretching and I see the change in the graph but I am still confused on the idea of Vertically stretching. INSTRUCTOR RESPONSE This is summarized at the very beginning of the section in the text. When you multiply a function by c, you move every point | c | times as far from the x axis. It's as if you grabbed along of the top and bottom of the graph and stretched it out factor c (if | c | < 1 it's actually as if you compressed the graph). If c is negative the graph also reflects through the x axis. This is a typical precalculus topic. If your precalculus or analysis course didn't cover this you might want to consider at least reading through, and perhaps working through at least some of the relevant parts of the following documents, which among other things provide a detailed introduction to understanding the concepts of stretching and shifting graphs: http://vhcc2.vhcc.edu/dsmith/genInfo/qa_query_etc/pc1/pc1_qa5.htm http://vhcc2.vhcc.edu/pc1fall9/Assignments/assignment_98126_function%20_families.htm http://vhcc2.vhcc.edu/pc1fall9/pc1/basic_point_graphs_identifying_equation.htm http://vhcc2.vhcc.edu/dsmith/genInfo/qa_query_etc/pc1/pc1_qa6.htm http://vhcc2.vhcc.edu/pc1fall9/basic_function_families/basic_function_families.htm< &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q Give the equation of the function. Describe your sketch in detail. Explain what effect, if any, it would have on the graph if we were to reverse the order of the transformations. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: y=2x^2 + 1, the lowest point being (0,1) and the graph is a parabola. For a parabola, I do not believe it effects the graph. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** The function would be y = f(x) = 2 x^2 + 1. The factor 2 stretches the y = x^2 parabola verticall and +1 shifts every point of the stretched parabola 1 unit higher. The result is a parabola which is concave up with vertex at point (0,1). The parabola has been stretched by a factor of 2 as compared to a x^2 parabola. If the transformations are reversed the the graph is shifted downward 1 unit then stretched vertically by factor 2. The vertex, for example, shifts to (0, -1) then when stretched shifts to (0, -2). The points (-1, 1) and (1, 1) shift to (-l, 1) and (1, 0) and the stretch leaves them there. The shift would transform y = x^2 to y = x^2 - 1. The subsequent stretch would then transform this function to y = 2 ( x^2 - 1) = 2 x^2 - 2. The reversed pair of transformations results in a parabola with its vertex at (0, -2), as opposed to (0, -1) for the original pair of transformations. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): I am not sure I understand what tansformations are being referred to.
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Given Solution: ** You have to first find g(1), then apply f to that value. To find g(1), you note that this is g(x) for x = 1. So you look on the x-axis where x = 1. Then you move up or down to find the point on the graph where x = 1 and determine the corresponding y value. On this graph, the x = 1 point lies at about y = 2. Then you look at the graph of f(x). You are trying to find f(g(1)), which we now see is f(2). So we look at the x = 2 point on the x-axis and then look up or down until we find the graph, which for x = 2 lies between 0 and 1, closer to 0. The value is about .3, give or take .1.. ** We can summarize this using function notation: f(g(1)) = f(2) = .3 (estimated) Further note: It appears from the graph that g(1) might be a little greater than 2, in which case f(g(1)) might be closer to .4. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q problem Graph the function f(x) = x^2 + 3^x for x > 0. Decide if this function has an inverse. If so, find the approximate value of the inverse function at x = 20. YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: as long as x remains positive, there should be an inverse, and the graph just shoots up the farther right you go, exponentially. at any rate finding the x value for when f(x)=20 using trial and error I have obtained a little over 2.4134 confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: ** The inverse of a function at a certain value is the x that would give you that value when plugged into the function. At x = 20 for g(x) = x^2 + 3^x is the x value for which x^3 + 3^x = 20. The double use of x is confusing and way the problem is stated in the text isn't as clear as we might wish, but what you have to do is estimate the required value of x. It would be helpful to sketch the graph of the inverse function by reflecting the graph of the original function through the line y = x, or alternatively and equivalently by making an extensive table for the function, then reversing the columns. ** BEGINNING OF STUDENT SOLUTION I started by graphing the function of y=x^2+3^x and y=x. INSTRUCTOR RESPONSE You don't say how you constructed the graph. If you used a graphing calculator, your solution would not be acceptable. It would be OK to use the calculator to check out your construction, but you would have to explain your construction of the graph. One description of the construction: From knowledge of basic power and exponential functions, you should know that x^2 and 3^x are both increasing functions for x > 0 (x^2 is decreasing for x < 0, but for the purpose of this question that doesn't matter). It should be clear why this is so. The greater the positive number you square, the greater the result. And the greater the value of x, the greater the power to which you raise 3, so the greater will be the value of 3^x. The graph of x^2 goes through (0, 0) and (1, 1). The graph of 3^x goes through (0, 1) and (1, 3). As x values continue to increase, the value of x^2 quickly becomes insignificant compared to that of 3^x (e.g., for x = 4 the function x^2 takes value 16 while 3^x takes value 81; for x = 8 we have x^2 = 64 and 3^x = 8261 (check my mental arithmetic on that one) ). So the graph of x^2 + 3^x passes through (0, 1) and (1, 4), and continues increasing more and more quickly as x increases. The resulting function is clearly invertible. It would also be OK to make a table. You should be able to do enough mental arithmetic to do so without relying on a calculator. Certainly you can square the integers from, say, 0 to 5. And you should be able to start with 3 and triple your result, repeating at least 5 times. x x^2 3^x x^2 + 3^x 0 0 1 1 1 1 3 4 4 2 4 9 13 13 3 9 27 36 36 4 16 81 77 77 5 25 343 368 368 A small portion of the graph is depicted below: The values of x and x^2 + 3^x can easily be reversed, giving us a partial table of the inverse function: x inv fn 1 0 4 1 13 2 37 3 77 4 368 5 It should be clear that the inverse function is single-valued (i.e., there is are no two x values greater than 0 for which the inverse function takes the same value). A partial graph of the inverse function (not to exactly the same scale as the original) is depicted below: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK ********************************************* Question: `q If H = f(t) describes the temperature H of an object at clock time t, then what does it mean to say that H(30)=10? What information would you get from the vertical and horizontal intercepts of the graph of the function? if f(t)=H and H(30)=10 then f(t) would also equal ten meaning f(t)=H(?) at f(30)=10 10=f(30) so at 30 seconds the temperature was 10 it seems the Temperature relies on the time, so the x-axis would be time, and the y-axis the Temperature. Thats the only specific information that can be concluded, knowing that intercepts are at (0,value) and (value,0) to their respective intercepts. confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: H is the temperature, t is the clock time. H(30) is the temperature at clock time t = 30, so H(30) = 10 tells us that a clock time t = 30 the temperature was 10 degrees. The vertical coordinate is the temperature, and the vertical intercept of the graph occurs when t = 0 so the vertical intercept gives us the temperature at clock time 0. The vertical coordinate is the clock time, and the horizontal intercept occurs when H = 0, so the horizontal intercept gives us the clock time when temperature is 0. &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary):OK ------------------------------------------------ Self-critique Rating:OK """ Self-critique (if necessary): ------------------------------------------------ Self-critique rating: """ Self-critique (if necessary): ------------------------------------------------ Self-critique rating: #*&!