Math Liberal Arts

#$&*

course MTH 151

01/14/13 2:20

Question: `q001. Consider the statement 'If that group of six-year-olds doesn't have adult supervision, they won't act in an orderly manner.' Under which of the following circumstances would everyone have to agree that the statement is false?

The group does have supervision and they do act in an orderly manner.

The group doesn't have supervision and they don't act in an orderly manner.

The group doesn't have supervision and they do act in an orderly manner.

The group does have supervision and they don't act in an orderly manner.

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Your solution:

The group doesn't have supervision and they do act in an orderly manner.

confidence rating #$&*:

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3

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Given Solution:

`aThe statement says that if the group doesn't have supervision, they will not act in an orderly manner. So if they don't have supervision and yet do act in an orderly manner the statement is contradicted.

If the group does have supervision, the statement cannot be contradicted because condition of the statement, that the group doesn't have supervision, does not hold. The statement has nothing to say about what happens if the group does have supervision.

Of course if the group doesn't have supervision and doesn't act in orderly manner this is completely consistent with the statement.

Therefore the only way to statement can be considered false is the group doesn't have supervision and does act in an overly manner.

Note that what we know, or think we know, about childrens' behavior has nothing at all to do with the logic of the situation. We could analyze the logic of a statement like 'If the Moon is made of green cheese then most six-year-olds prefer collard greens to chocolate ice cream'. Anything we know about the composition of the Moon or the tastes of children has nothing to do with the fact that the only way this statement could be shown false would be for the Moon to be made of green cheese and most six-year-olds to prefer the ice cream.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q002. List the different orders in which the letters a, b and c could be arranged (examples are 'acb' and 'cba'). Explain how you know that your list contains every possible order.

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Your solution:

A B C

A C B

B A C

B C A

C B A

C A B

confidence rating #$&*:

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Given Solution:

`aThe only reliable way to get all possible orders is to have a system which we are sure the list every order without missing any.

Perhaps the simplest way to construct all possible orders is to list then alphabetically.

We start with abc. There is only one other order that starts with a, and it is obtained by switching the last two letters to get acb.

The next alphabetical order must start with b. The first possible listing starting with b must follow b with a, leaving c for last. The orders therefore bac. The only other order starting with b is bca.

The next order must start with c, which will be followed by a to give us cab. The next order is obtained by switching the last two letters to get cba.

This exhausts all possibilities for combinations of the three letters a, b and c. Our combinations are, in alphabetical order,

abc, acb, bac, bca, cab, cba.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q003. One collection consists of the letters a, c, d and f. Another collection consists of the letters a, b, d and g.

List the letters common to both collections.

List the letters which appear in at least one of the collections.

List the letters in the first half of the alphabet which do not appear in either of the collections.

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Your solution:

A D

A C D F B G

E H I J K L M

confidence rating #$&*:

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3

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Given Solution:

`aTo letters a and d each appear in both collections. No other letter does.

The letters a, c, d, and f appear in the first collection, so they all in at least one of the collections. In addition to letters b and g appear in the second collection. Therefore letters a, b, c, d, f and g all appear in at least one of the collections.

We consider the letters in the first half of the alphabet, in alphabetical order. a, b, c and d all appear in at least one of the collections, but the letter e does not. The letters f and g also appear in at least one of the collections, but none of the other letters of the alphabet do. The first half of the alphabet ends at m, so the list of letters in the first half of the alphabet which do not occur in at least one of the collections is e, h, i, j, k, l, m.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q004. Give the next element in each of the following patterns and explain how you obtained each:

2, 3, 5, 8, 12, ...

3, 6, 12, 24, ...

1, 3, 4, 7, 11, 18, ...

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Your solution:

2, 3, 5, 8, 12, 17 first add 1, then 2, then 3, then 4, then 5

3, 6, 12, 24, 48 multiply the next number by 2

1, 3, 4, 7, 11, 18, 29 add the first two numbers to get the next number

confidence rating #$&*:

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3

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Given Solution:

`aThe pattern of the sequence 2, 3, 5, 8, 12, ... can be seen by subtracting each number from its successor. 3-2 = 1, 5-3 = 2, 8-5 = 3, 12-8 = 4. The sequence of differences is therefore 1, 2, 3, 4, ... . The next difference will be 5, indicating that the next number must be 12 + 5 = 17.

The pattern of the sequence 3, 6, 12, 24, ... can be discovered by dividing each number into its successor. We obtain 6/3 = 2, 12/6 = 2, 24/12 = 2. This shows us that we are doubling each number to get the next. It follows that the next number in the sequence will be the double of 24, or 48.

The pattern of the sequence 1, 3, 4, 7, 11, 18, ... is a little obvious. Starting with the third number in the sequence, each number is the sum of the two numbers proceeding. That is, 1 + 3 = 4, 3 + 4 = 7, 4 + 7 = 11, and 7 + 11 = 18. It follows that the next member should be 11 + 18 = 29.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q005. The number 18 can be 'broken down' into the product 9 * 2, which can then be broken down into the product 3 * 3 * 2, which cannot be broken down any further . Alternatively 18 could be broken down into 6 * 3, which can then be broken down into 2 * 3 * 3.

Show how the numbers 28 and 34 can be broken down until they can't be broken down any further.

Show that there at least two different ways to break down 28, but that when the breakdown is complete both ways end up giving you the same numbers.

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Your solution:

28 28 34

14*2 4*7 17*2

7*2*2 2*2*7

confidence rating #$&*:

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3

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Given Solution:

`aA good system is to begin by attempting to divide the smallest possible number into the given number. In the case of 34 we see that the number can be divided by 2 give 34 = 2 * 17. It is clear that the factor 2 cannot be further broken down, and is easy to see that 17 cannot be further broken down. So the complete breakdown of 34 is 2 * 17.

To breakdown 28 we can again divide by 2 to get 28 = 2 * 14. The number 2 cannot be further broken down, but 14 can be divided by 2 to give 14 = 2 * 7, which cannot be further broken down.Thus we have 28 = 2 * 2 * 7.

The number 28 could also the broken down initially into 4 * 7. The 4 can be further broken down into 2 * 2, so again we get 28 = 2 * 2 * 7.

It turns out that the breakdown of a given number always ends up with exactly same numbers, no matter what the initial breakdown.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q006. Give the average of the numbers in the following list: 3, 4, 6, 6, 7, 7, 9. By how much does each number differ from the average?

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Your solution:

6 = AVERAGE

3 : 3

4 : 2

6 : 0

7 : 1

9 : 3

confidence rating #$&*:

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OK

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Given Solution:

`aTo average least 7 numbers we add them in divide by 7. We get a total of 3 + 4 + 6 + 6 + 7 + 7 + 9 = 42, which we then divide by 7 to get the average 42 / 7 = 6.

We see that 3 differs from the average of 6 by 3, 4 differs from the average of 6 by 2, 6 differs from the average of 6 by 0, 7 differs from the average of 6 by 1, and 9 differs from the average of 6 by 3.

A common error is to write the entire sequence of calculations on one line, as 3 + 4 + 6 + 6 + 7 + 7 + 9 = 42 / 7 = 6. This is a really terrible habit. The = sign indicates equality, and if one thing is equal to another, and this other today third thing, then the first thing must be equal to the third thing. This would mean that 3 + 4 + 6 + 6 + 7 + 7 + 9 would have to be equal to 6. This is clearly not the case. It is a serious error to use the = sign for anything but equality, and it should certainly not be used to indicate a sequence of calculations.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q007. Which of the following list of numbers is more spread out, 7, 8, 10, 10, 11, 13 or 894, 897, 902, 908, 910, 912? On what basis did you justify your answer?

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Your solution:

894, 897, 902, 908, 910, 912

There is more spacing between the numbers

confidence rating #$&*:

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3

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Given Solution:

`aThe first set of numbers ranges from 7 to 13, a difference of only 6. The second set ranges from 894 to 912, a difference of 18. So it appears pretty clear that the second set has more variation the first.

We might also look at the spacing between numbers, which in the first set is 1, 2, 0, 1, 2 and in the second set is 3, 5, 6, 2, 2. The spacing in the second set is clearly greater than the spacing in the first.

There are other more sophisticated measures of the spread of a distribution of numbers, which you may encounter in your course.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q008. 12 is 9 more than 3 and also 4 times 3. We therefore say that 12 differs from 3 by 9, and that the ratio of 12 to 3 is 4.

What is the ratio of 36 to 4 and by how much does 36 differ from 4?

If 288 is in the same ratio to a certain number as 36 is to 4, what is that number?

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Your solution:

36 differs from 4 by 32

The ratio of 36 is 4 by 9

The ratio of 288 is 32 by 9

confidence rating #$&*:

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3

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Given Solution:

`aJust as the ratio of 12 to 3 is 12 / 3 = 4, the ratio of 36 to 4 is 36 / 4 = 9. 36 differs from 4 by 36 - 4 = 32.

Since the ratio of 36 to 4 is 9, the number 288 will be in the same ratio to a number which is 1/9 as great, or 288 / 9 = 32.

Putting this another way, the question asks for a 'certain number', and 288 is in the same ratio to that number as 36 to 4. 36 is 9 times as great as 4, so 288 is 9 times as great as the desired number. The desired number is therefore 288/9 = 32.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q009. A triangle has sides 3, 4 and 5. Another triangle has the identical shape of the first but is larger. Its shorter sides are 12 and 16. What is the length of its longest side?

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Your solution:

20 is the length of the longest side

confidence rating #$&*:

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3

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Given Solution:

`a** You need to first see that that each side of the larger triangle is 4 times the length of the corresponding side of the smaller. This can be seen in many ways, one of the most reliable is to check out the short-side ratios, which are 12/3 = 4 and 16/4 = 4. Since we have a 4-to-1 ratio for each set of corresponding sides, the side of the larger triangle that corresponds to the side of length 5 is 4 * 5 = 20. **

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q010. List the different orders in which John, Mary and Sally can be lined up, from left to right, for a picture.

In how many orders can the three be lined up so that the two women are next to each other?

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Your solution:

Mary, Sally, John

Sally, Mary, John

John, Sally, Mary

John, Mary, Sally

Mary, John, Sally

Sally, John, Mary

the above list includes all possible orders

Mary, Sally, John

this duplicates an ordering you listed previously

Sally, Mary, John

this duplicates an ordering you listed previously

John, Sally, Mary

this duplicates an ordering you listed previously

John, Mary, Sally

this duplicates an ordering you listed previously

confidence rating #$&*:

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3

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Question: `q010. If John is next to Mary, Sally will be jealous. Sally is jealous. Does it logically follow that John is next to Mary? Explain.

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Your solution:

Yes because Sally is jealous

confidence rating #$&*:

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Question: `q010. By how much does each of the numbers 81, 85, 89, 83, 86, 86 differ from the average of the six numbers? The average is a whole number, and you should be able to figure out the number without using a calculator.

Explain how you got your solution.

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Your solution:

81+ 85+89+ 83+86+86=510

510/6=85

81 : 4

83 : 2

85 : 0

89 : 4

86 : 1

confidence rating #$&*:

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3

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