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phy 201
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_05.1_labelMessages **
The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
8*3s = 24
24 + 12= 36 cm/s
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
36 + 12= 48/2 = 24 cm/s
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36 + 12= 48/2 = 24
implies that
36 + 12 = 24.
48/2 = 24 cm/s is not true. There is no cm/s on the left-hand side.
What you mean is
(36 cm/s + 12 cm/s) / 2 = 48 cm/s /2 = 24 cm/s
Each of these expressions is equal to any of the others, which is what the = sign means.
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That said, I know what you intend, and that you have found that vAve is 24 cm/s.
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
24 cm/s * 3 = 72 cm
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24 cm/s * 3 = 72 cm/s.
24 cm/s * 3 s = 72 cm.
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*#&!
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Your thinking is right throughout, as are your final results.
Your details need to be expressed a little more tightly.
Check my notes.
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