course Phy 121 Ï’Ê„±Œ˜¦µí¸{ݯþ“Ý÷J ŸÝyËŒcù±Šüassignment #002
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13:20:00 `q001. Note that there are 14 questions in this assignment. If an object moves 12 meters in 4 seconds, then at what average rate is the object moving? Explain how you obtained your result in terms of commonsense images.
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RESPONSE --> 12/4=3meters per hour confidence assessment: 1
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13:20:53 `q002. How is this problem related to the concept of a rate?
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RESPONSE --> It tells how fast the object moving takes. confidence assessment: 1
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13:21:27 `q003. Is object position dependent on time or is time dependent on object position?
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RESPONSE --> the time dependent on object position confidence assessment: 1
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13:22:31 `q004. So the rate here is the average rate at which position is changing with respect to clock time. Explain what concepts, if any, you missed in your explanations.
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RESPONSE --> I didn't understand at first that the average rate depended on position of the object. confidence assessment: 1
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13:23:31 `q005. If an object is displaced -6 meters in three seconds, then what is the average speed of the object what is its average velocity? Explain how you obtained your result in terms of commonsense images and ideas.
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RESPONSE --> -6/3=-2meters per seconds confidence assessment: 1
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13:24:31 `q006. If `ds stands for the change in the position of an object and `dt for the time interval during which the position changes, then what expression stands for the average velocity vAve of the object during this time interval?
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RESPONSE --> 'dv I think would be it. confidence assessment: 0
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13:25:34 `q007. How do you write the expressions `ds and `dt on your paper?
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RESPONSE --> Position change/clock time confidence assessment: 0
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13:27:23 `q008. If an object changes position at an average rate of 5 meters/second for 10 seconds, then how far does it move? How is this problem related to the concept of a rate?
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RESPONSE --> 5*10=50 meters/second confidence assessment: 0
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13:31:25 `q009. If vAve stands for the rate at which the position of the object changes (also called velocity) and `dt for the time interval during which the change in position is to be calculated, then how to we write the expression for the change `ds in the position?
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RESPONSE --> I have no idea how to do that. confidence assessment: 0
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13:33:05 `q010. Explain how the quantities average velocity vAve, time interval `dt and displacement `ds are related by the definition of a rate, and how this relationship can be used to solve the current problem problem.
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RESPONSE --> You can use this to find the average velocity. confidence assessment: 0
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13:34:49 `q011. The basic rate relationship vAve = `ds / `dt expresses the definition of average velocity vAve as the rate at which position s changes with respect to clock time t. What algebraic steps do we use to solve this equation for `ds, and what is our result?
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RESPONSE --> I have no idea confidence assessment: 0
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13:35:22 `q012. How is this result related to our intuition about the meanings of the terms average velocity, displacement and clock time?
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RESPONSE --> It helps to solve those questions confidence assessment: 0
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13:36:04 `q013. What algebraic steps do we use to solve the equation vAve = `ds / `dt for `dt, and what is our result?
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RESPONSE --> vAve=result of 'ds/'dt confidence assessment: 0
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13:36:41 `q014. How is this result related to our intuition about the meanings of the terms average velocity, displacement and clock time?
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RESPONSE --> It helps to answer those questions confidence assessment: 0
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You then start the process over with the next question, clicking on the Next Question/Solution button at top left, etc. &#