Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
Over an unspecified distance, the ball’s velocity increased by an average of 6 cm/sec.
I guess that because it ended and 10cm/sec and if I subtract the initial velocity of 4 cm/sec then the result averages in 6 cm/sec.
10 cm/s and 4 cm/s average out to 7 cm/s
answer/question/discussion:
• Without further information, why is this just a guess?
This is just a guess because a result of 6 cm/sec is just an average. It is just an average because I don’t know the velocity at any given point in the ball’s travel. There might be other points in which the ball was slower or faster. Thus only an average can be given.
answer/question/discussion:
• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
I guess that it takes 3 seconds for a ball to increase its velocity by 6 cm/sec then the distance traveled might be 18 cm. I came up with this solution by averaging 6 cm/sec over 3 seconds with a result of 18cm.
answer/question/discussion:
• At what average rate did its velocity change with respect to clock time during this interval?
The average would have been an average of 2 cm/sec change in velocity. This is a result of dividing 6cm/s by 3s.
answer/question/discussion:
Good, but 6 cm/s / (3 s) = 2 cm/s^2, not 2 cm/s.
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15 mins
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Would like to have feedback. Thanks, Joshua
Minor arithmetic error in estimating average velocity and a units error on the last question, but overall very good.
&#Let me know if you have questions. &#