Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
F=5kg*9.8m/s^2, f=49N
F=6kg*9.8m/s^2, F=58.8N
Fnet=58.8N-49N, Fnet=9.8N
The direction will be in that of the 6kg mass and the magnitude of acceleration will be 9.8N/11kg = .89m/s^2
answer/question/discussion:
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
I think that I must have missed something somewhere because I am having a hard time with this question and am having a hard time finding some information to help me with this.
This tells you that the initial speed is 1.8 meters / second. You have calculated the acceleration, and you are given a 1-second time interval. All you need to do is choose your positive direction and you'll know v0, a and `dt. From this you can find vf, `ds, `dv and vAve for the given interval. Then you need only interpret these quantities.
answer/question/discussion:
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
The two should be in opposite directions as velocity will be increasing to zero and acceleration will be decreasing to the acceleration of the system. The system will slow down.
answer/question/discussion:
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1 hour
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Would like ot have feedback. Thanks, Joshua
You've got everything you need; see my note. I think the situation will become clear, but if it doesn't be sure to let me know.
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