course Mth 272 ?????Sw???????E??assignment #015015.
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20:52:50 Query problem 6.2.2 integrate x e^(-x)
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RESPONSE --> first find all the parts u=x du=dx dv=e^-x v= -e^-x then use the integ by parts formula -xe^-x - e^-x +c then factor (e^-x)(-x-1) +c confidence assessment: 3
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20:53:01 What is the indefinite integral?
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RESPONSE --> answered confidence assessment: 3
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20:53:14 What did you use for u and what for dv, what were du and v, and what integral did you obtain?
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RESPONSE --> answered confidence assessment: 3
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21:08:45 Query problem 6.2.3 integrate x^2 e^(-x)
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RESPONSE --> finding the parts u=x^2 du=2xdx dv=e^-xdx v=-e^-x -x^2e^-x+2 ~ xe^-xdx the parts are the same as the last question so i don't have to do them all over again -x^2e^-x+2[-xe^-x-e^-x]+c -x^2e^-x-2xe^-x-2e^-x+c factor = (e^-x)(-x^2-2x-2) + c confidence assessment: 3
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21:08:53 What is the indefinite integral?
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RESPONSE --> answered confidence assessment: 3
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21:09:01 For your first step, what was u and what was dv, what were du and v, and what integral did you obtain?
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RESPONSE --> answered confidence assessment: 3
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21:09:11 Answer the same questions for your second step.
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RESPONSE --> answered confidence assessment: 3
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21:23:38 Query problem 6.2.18 integral of 1 / (x (ln(x))^3)
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RESPONSE --> you actually don't have to use integration by parts for this one. u= ln(x) du= 1/x dx ~ 1/(lnx)^3dx = ~ lnx^-3 dx then use the power rule lnx^-2/ -2 = -1/2lnx^2 + c confidence assessment: 3
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21:23:47 What is the indefinite integral?
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RESPONSE --> answered confidence assessment: 3
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21:23:56 What did you use for u and what for dv, what were du and v, and what integral did you obtain?
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RESPONSE --> answered confidence assessment: 3
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21:37:41 Query problem 6.2.32 (was 6.2.34) integral of ln(1+2x)
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RESPONSE --> this on doesn't require integration by parts either u= 1+2x du=2dx 1/2 ~ ln (1+2x)dx 1/2[(1+2x)ln(1+2x)] - x + c [(1+2x) ln(1+2x)/ (2)] -x + c i used the logarithmic rule that states the integral of lnxdx = xlnx- x + c
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21:37:48 What is the indefinite integral?
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RESPONSE --> answered confidence assessment: 3
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21:37:55 What did you use for u and what for dv, what were du and v, and what integral did you obtain?
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RESPONSE --> answered confidence assessment: 3
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21:38:29 Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> I understood all of this assignment, and it was helpful to see all the problems in the book. confidence assessment: 3
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