course Phy201 Could you check this and make sure that I answered all of the questions. I received a subscript error and it closed. So I am not sure if I made it all the way through. ????wE?N?f???????assignment #001
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15:36:45 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> Find the mean of the sample. Compare each sample to the sample mean to see how much each deviate from it. Take the sqrt of the mean of the square of the deviations confidence assessment: 3
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15:38:19 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> You find a line that best represents the data, the uncertainties lie in which points you choose to find the equation. Two people can choose two different sets of points causing each to have different equations. confidence assessment: 3
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15:41:16 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> velocity is distance divided by time. I believe this is an example of rate because, for example, 5m/sec would mean it travels 5 meters every second, basically a rate at which it travels. confidence assessment: 3
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15:41:32 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> ok self critique assessment: 3
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15:42:04 Given average speed and time interval how do you find distance moved?
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RESPONSE --> mulitply average speed by time confidence assessment: 3
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15:42:15 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> ok self critique assessment: 3
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15:44:12 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> Average speed divided by distance confidence assessment: 3
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15:45:21 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> Yes I had my fraction upside down when I calculated it and realized it too late. self critique assessment: 3
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15:47:23 Given time interval and distance moved how do you get average speed?
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RESPONSE --> speed is distance/time interval confidence assessment: 3
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15:47:34 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> ok self critique assessment: 3
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