Phy 231
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: Here we have a graph with velocity in cm/s on the y-axis, and time in seconds on the x-axis. I then gave the x-axis intervals of 1 s from 1 s to 10 s, and the y-axis intervals of 5 cm/s from 0 cm/s to 50 cm/s. On this graph we have two dots representing the points (4, 10) and (9, 40) which represent values 10 cm/s at 4 seconds, and 40 cm/s at 9 seconds correspondingly.
Sketch a straight line segment between these points.
answer/question/discussion: We see a positive slope rising from (4, 10) to (9, 40).
What are the rise, run and slope of this segment?
answer/question/discussion: Rise = 40 – 10 = 30 with units of cm/s; run = 9 – 4 = 5 in units of seconds; and slope equal 30/ 5 = 6 in units of cm/s^2.
What is the area of the graph beneath this segment?
answer/question/discussion: The area of this graph would be given by [(40 + 10 )/2] * (9-4) = 125 in units of cm, because we are finding product of the average height of the graph and its width, which is how the area of a trapezoid is calculated.
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8 minutes
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This is the first of the many assignments I promised you. If I have properly followed and completed assignments without missing anything I will now be spending some time submitting to you all assignments that I do not have from here through a completed Assignment 11 group. I'm so glad you said you wouldn't mind a 'few' extra assignments to grade. I hope the work completed is satisfactory in quality and progress I have made is what you expected me to have done by this point. At my current rate since I have been working hard from the start of the New Year I should be finished with the course near the end of the month, and that is hopefully correctly accounting for the amount of work I will have to do for my other courses that I start Monday the 12th.
Very good.