Phy 231
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: F = ma; therefore, F = 12 kg * 3 m/s^2 = 36 N
What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: a = F/ m; therefore, 20 N/ 4 kg = 5 m/s^2 = a
If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: Because without opposing forces 20 N of force acting upon 10 kg of mass would provide 20 N/ 10 kg = 2 m/s^2; therefore, since the object only had 1.5 m/s^2 acceleration there were opposing forces of 5 N in the opposite direction of the 20 N force.
What is the total of all those forces and in what direction does this total act?
answer/question/discussion: The net force would then be 20 N + ( -5 N) = 15 N in the direction applied by by the 20 Newtons of force. The 5 N of force was determined by find that 2 m/s^2 acceleration was .5 m/s^2 greater than resulting 1.5 m/s^2 acceleration; therefore, to account for the lost .5 m/s^2 acceleration on a 10 kg mass we find that 10 kg * .5 m/s^2 = 5 N in a direction opposing the 20 N of force.
** **
15 minutes
** **
&#Very good responses. Let me know if you have questions. &#