Phy 231
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: The 6 kg mass will experience force equal to 6 kg * 9.8 m/s^2 = 58.8 N, and the 5 kg mass experience force equal to 5 kg * 9.8 m/s^2 = 49 N; therefore, 58.8 N – 49 = 9.8 N = Fnet; therefore, the system will experience an acceleration of 9.8 N/ (5 kg + 6 kg) = 0.89 m/s^2 = a.
If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: This will be solved by the distance equation of 'ds = 0 m + 1.8 m/s (1)+ (- .89 m/s^2) (1)^2 = 1.8 m - .89 m = .91 m. This indicates that after the initial push it will travel .91 m in 1 second in the downwards direction, because we treated downwards direction as positive; therefore, the acceleration of the system that is in the direction of the 6 kg mass is treated as negative from the reference frame.
During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: During the first second the acceleration is against the motion of system, which means that it is acting as a retarding force and slowing the system's velocity down.
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10 minutes
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This is the first assignment that I worked on today and did not submit from a backup file; consequently and errors I may have made with the submission of the previous assignments earlier today should not be repeated from this point.
&#This looks very good. Let me know if you have any questions. &#