Phy 231
Your 'cq_1_7.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: 2 m = 0 m/s + (.5a)(.64s)^2 = 10. m/s^2 =a\
2 m is not equal to 10 m/s^2. Careful about the use of the = sign, here and below.
Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: 5m = 0 m/s + (.5a)(.64s)^2 = 9. m/s^2 = a
Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: No they are not; however, the first answer was much closer than what I wrote, but due to significant figures I could not give an answer with more than one significant figure. Otherwise I would have give 9.72 as the answer for the first question, which is much closer to the accepted value of gravitational constant.
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10 minutes
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&#Your work looks good. See my notes. Let me know if you have any questions. &#