Phy 231
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
What will be the velocity of the ball after one second?
answer/question/discussion: 25 m/s – 10 m/s^2(1s) = 15 m/s
What will be its velocity at the end of two seconds?
answer/question/discussion: 25 m/s – 10 m/s^2(2s) = 5 m/s
During the first two seconds, what therefore is its average velocity?
answer/question/discussion: (25 m/s + 5 m/s)/2 = 15 m/s
How far does it therefore rise in the first two seconds?
answer/question/discussion: 15 m/s (2s) = 30 m
What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: - 5 m/s and -15 m/s
At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: 2.5 seconds
What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: 5 m/s, and 20 m.
How high will it be at the end of the sixth second?
answer/question/discussion: 0 m, the ground
the ground is not mentioned in the problem, and shouldn't be assumed
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15 minutes11-83-020
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Good, except for your last answer. You should be able to fix that easily.
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