Phy 231
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
Sketch the force and its component in the direction of motion, as well as its component perpendicular to the direction of motion.
answer/question/discussion: If we give both objects a starting point of the origin then we find that there is one object moving into the second quadrant, and a force that is moving along the negative y-axis or straight down.
Suppose you are facing in the direction of motion. Do you perceive the component of the force in the direction of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: I would perceive the force to be backwards in reference to the motion of the object, or opposite to the direction of motion.
Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: It will slow down, because the force will have have an effect upon the mass of a negative acceleration.
If you are facing in the direction of motion, then the directions perpendicular to the direction of motion will be to your right and to your left. Is the component of the force perpendicular to the direction of motion to the right or to the left?
answer/question/discussion: The force perpendicular to the motion of the object would be acting from the right direction, which means that it would be pushing the object in a direction to the left.
Will the veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: As stated above the object would veer to the left.
Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: The component of motion along the line of motion.
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15 minutes
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No need to revise, but see the link.
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#