Phy 231
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: We can find the acceleration by the equation v^2/r = a; therefore, (.3 m/s)^2/.2 m = 0.45 m/s^2
What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: We know the acceleration and mass of the steel ball; therefore, the F = ( .11 kg) * (.45 m/s^2) = 0.0495 N is the force of the centripetal motion.
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5 minutes
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&#Very good work. Let me know if you have questions. &#