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course phy 201
If an object increases velocity at a uniform rate from 8 m/s to 27 m/s in 13 seconds, what is its acceleration and how far does it travel?Sketch a velocity vs. clock time graph for an object whose initial velocity is 8 m/s and whose velocity 13 seconds later is 27 m/s. Explain what the slope of the graph means and why, and also what the area means and why.
(27m/s-8m/s)/13s=1.5m/s/s
19m/s=(`ds/13s) = 247m
The slope of the graph means the acceleration at the time. The rise is the velocity and the run is the time.
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Very good.
No need to revise but note that
19m/s=(`ds/13s) = 247m
is not correct. I know what you mean but 19 m/s is not equal to 247 m.
19m/s=(`ds/13s)
`ds = 247m
would be fine.
No need to revise. But try to restrict the use of the = sign to quantities that are in fact equal.
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