#$&*
phy 201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
Aave= (vf-vo)/(tf-to)=(10/5-10/8)/3 = .25m/s^2
#$&*
*#&!*#&!*#&!
@&
(vf - v0) / (tf - t0) is not equal to vf / tf - v0 / t0. Consider that (10 - 5) / (8 - 3) = 5/3, while 10/5 - 8/3 is -1/3.
In any case there is no 3-second time interval involved in this problem. There is one trial where the car rolls down one incline, and a completely different trial where it rolls down the other. For each trial you have an initial, final and average velocity, a time interval, a displacement and an acceleration.
Having found the two values of the accleeration, you then need to apply the definition of average rate of change.
*@
*#&!*#&!
@&
&#Please see my notes and submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes. &#
*@