course Phy 201 WyjWҢnx牵ȃpݒassignment #000
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11:37:54 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
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RESPONSE --> To measure my understanding of the basic ideas about motion and timing and procesures associated with them.
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11:41:37 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
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RESPONSE --> Average speed = displacement/elapsed time=final position-intital position/elapsed time. confidence assessment: 0
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11:46:31 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
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RESPONSE --> 40cm/5s=8cm/s is the average velocity on the incline. I am not sure at this point I can relate my experience to this question. I know that this would be similar to being in a car that traveled down a hill 40 cm in 5 seconds would give me the average velocity if I devide the diplacement by the time. I do know that I am not to confuse this with average speed which is the total distance traveled divided by the elapsed time. confidence assessment: 1
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11:48:39 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
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RESPONSE --> Half of 40cm is 20cm therefore 20/3=6.6 cm/s is the average velopicty on the first half and the second half velocity would be 20/2=10 cm/s. confidence assessment: 2
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11:54:15 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> A. The time will have some % of uncertainty say .2 s per interval. B. Human error would be more than likely a suitable culperate for the lack or uncertainty in time intervals since reaction time could be part of the time differences. C. If the object's incline is the same then the times it takes should not be different unless there are other factors such as the human error or timer error. D. There could be some differences in the position of the object but I would think they should be extremely slight. E. The degree of uncertainty here could be more of a discrepancy since this would be the same as B. Human error can occur since everyone is different and may release slower once than before or start in a different area than previously or stop the timer later or earlier than they should. confidence assessment: 2
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11:55:35 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> A. 2% B. 20% C. 5% D. 4% E. 30% confidence assessment: 0
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11:59:25 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> A. There would not be much we could do about the timer unless you got two timers and used the one that seemed more accurate over several trials. B. We could use a group of people or a few people to determine the % of uncertainty between them to account for some error in the numbers in each trial. C. We could make a mark at the starting point and ending points to help us visualize where to start and stop more accurately during the trials. D. Again we could mark the spot so that we knew for certain we started from a designated point each time. E. Again mark the spot by drawing a line which would help us to know exactly when each time to stop the timer once we reached that point. We would still have some uncertainty but it could help us to be more accurate than before. confidence assessment: 2
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12:00:03 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> I am not sure since I have not gotten to this experiment at present. I am still waiting for my lab kit items to arrive. confidence assessment: 0
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12:02:01 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> They are both at the origin which lets us know that we are at the starting point, not x being on 3 and y beig on 4. They both are perpendicular to one another. confidence assessment: 1
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swހL\sϊ assignment #000 000. `Query 0 Physics I 01-20-2008
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12:24:20 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> Not yet completed this experiment. confidence assessment: 0
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12:24:38 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> confidence assessment:
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12:24:53 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> not yet done experiment confidence assessment: 0
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12:25:02 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> n a confidence assessment: 0
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12:28:32 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> 30 cm confidence assessment: 1
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12:29:47 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
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RESPONSE --> I understand this equation from the notes on average rate at which velocity changes page 3. self critique assessment: 3
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12:31:15 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I am not sure I understand in graphing the average rates and velocity as to how or why there is a difference in the X and Y axis. I know it is because of a change but I am not sure I fully understand what this is to tell us. . . confidence assessment: 3
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12:36:11 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I understand Distance = speed * time for example 4s*4m=16 m in problem 1. I also understand the avg. rate of change = change in postion/time. I am not sure about set 1 problem 3.
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