Introductory Questions-Answers

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course Mth 279

6/24 5:30

Your basic instructions follow. Rather than giving you the instructions at the beginning of the document, you were given a couple of questions to serve as a point of reference, and should now be better prepared to understand the instructions:1. Answer each question, then look at the given solution:

It is expected that you will answer each question before looking at the given solution. There is no grade penalty for looking ahead, but if you do you:

may be bypassing an opportunity to engage yourself in the solution process

run the risk of deluding yourself about what you understand

are likely to learn much less and

are not as likely to do well in the course.

However your instructor understands the tradeoffs involved in being a student, and makes no judgement about how you should use this material. As long as you use it to your best advantage and succeed on tests and other course activities, you will get a good result from this course.

2. If you can't readily work it out in your head, use pencil and paper, and keep a record of your work.

You aren't expected to work out your solutions by staring at a computer screen, though you will likely find many questions and problems easy enough to do 'in your head'. However on more challenging problems, it's easier to work things out using a handwritten document than a computer-created or word-processed document.

You should in general work out your answers to non-obvious problems on paper, jotting down sketches, diagrams and notes as you go, in such a way that you can make sense of it later. This will help you focus your work and maintain your train of thought, and will be quite valuable for periodic review. It is recommended (and may in some courses be required) that you dedicate a notebook to this course, and at least sketch out your work in the notebook.

3. There's no need for special formatting or graphs:

Don't use special characters in your responses (e.g., characters like a, D, r that don't appear on your keyboard). The characters on your keyboard suffice to answer all these questions. If you use special characters they won't come through the form you use to submit your work, and if you use too many such characters your instructor might not be able to tell what you are saying.

Don't try to make graphs in your document. Sketch your graphs by hand, then if necessary describe them in words (that probably won't be necessary in the present exercise; more about that later). Graphs won't come through when you submit your work. You can make a graph without understanding it, but you can't give a good description of your graph without understanding it. Your instructor doesn't need to see your graphs; he needs to see your descriptions of your graphs. The present exercise doesn't require extensive descriptions of graphs; it they apply to your course, you will see more about describing your graphs soon.

When you submit this document (per instructions at the end), it will come to the instructor in pure text format. Any formatting you have done will not be seen by the instructor, special characters will not appear in what the instructor sees, and graphs won't come through. So don't do any fancy formatting for the instructor. You will of course want to save your original copy, and you are welcome to add formatting for your own purposes.

4. Expect to see your work posted by the instructor in a timely manner:

After submitting your work, per instructions at the end of this document, you should expect to see your work posted, along with instructor commentary, at your access page. It should be posted by the evening of the day after you submit it, and may well be posted the evening of the same day.

You have probably submitted your answers the first two questions in a preceding task. You are welcome to answer them again, but if you have already submitted them you may go ahead and skip to the third question.

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Question: `q001. If you are earning money at the rate of 8 dollars / hour and work for 4 hours, how much money do you make during this time? Answer in such a way as to explain your reasoning as fully as possible. A solution to this problem appears several lines below, but enter your own solution before you look at the given solution.

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Your solution: (type in your solution starting in the next line)

Earning money occurs at a rate of 8 dollars / 1 hour. When multiplied by 4, the hour units appear as hour/hour, which cancel each other out. We are then left with

8 dollars * 4, which results in 32 dollars.

confidence rating #$&*:

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My confidence level is a 3.

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Given Solution: 8 dollars / hour means '8 dollars per hour', indicating that for every hour you work you earn 8 dollars. If you work for 4 hours, then if you earn 8 dollars for every one of those hours you earn 4 * 8 dollars = 32 dollars.

Self-critique :

My solution uses a purely mathematical and technical approach, whereas the given solution uses words and common sense to arrive at the same answer.

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Self-critique Rating:

My self-critique rating is a 3.

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Question: `q002. If you work 12 hours and earn $168, then at what rate, in dollars / hour, were you making money?

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Your solution:

We are looking for a solution with the units dollars / hour. With the given information, we can have those units with 168 dollars / 12 hours. 168 / 12 = 14.

We are left with 14 dollars / hour.

confidence rating #$&*:

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My confidence rating is a 3.

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Given Solution: $168 earned in 12 hours implies that $168 / 12 = $14 were made per hour, so the rate is $14 / hour.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

Here are the remaining ten questions:

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Question: `q003. If you are earning 8 dollars / hour, how long will it take you to earn $72? The answer may well be obvious, but explain as best you can how you reasoned out your result.

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Your solution:

We are looking for a solution with the units hours. The information given is in units dollars per hour. We can flip this to have units of 1 hour / 8 dollars.

We then multiply this by 72 dollars, which leaves us with units of hours. 72 / 8 = 9 dollars.

confidence rating #$&*:

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My confidence rating is a 3.

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Given Solution: Many students simply know, at the level of common sense, that if we divide $72 by $8 / hour we get 9 hours, so 9 hours are required.

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Self-critique (if necessary): If you are sure your solution matches the given solution, and/or are sure you completely understand the given solution, then just type in 'OK'.

OK

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Self-critique Rating:

OK

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Question: `q004. Calculate (8 + 3) * 5 and 8 + 3 * 5, indicating the order of your steps. Explain, as best you can, the reasons for the difference in your results.

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Your solution:

In the equation (8 + 3) * 5, we must first calculate the equation within parentheses. 8 + 3 = 11. We are then left with 11 * 5 = 55.

In the equation 8 + 3 * 5, we must begin with multiplication. 3 * 5 = 15. Then, 8 + 15 = 23.

confidence rating #$&*:

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3

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Given Solution: (8 + 3) * 5 and 8 + 3 * 5

To evaluate (8 + 3) * 5, you will first do the calculation in parentheses. 8 + 3 = 11, so

(8 + 3) * 5 = 11 * 5 = 55.

To evaluate 8 + 3 * 5 you have to decide which operation to do first, 8 + 3 or 3 * 5. You should be familiar with the order of operations, which tells you that multiplication precedes addition. The first calculation to do is therefore 3 * 5, which is equal to 15. Thus

8 + 3 * 5 = 8 + 15 = 23

The results are different because the grouping in the first expression dictates that the addition be done first.

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Self-critique (if necessary):

I did not specify that I was deriving my basic knowledge of which operations to do first from the Order of Operations.

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Self-critique Rating:

OK

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Question: `q005. Calculate (2^4) * 3 and 2^(4 * 3), indicating the order of your steps. Explain, as best you can, the reasons for the difference in your results. Note that the symbol '^' indicates raising to a power. For example, 4^3 means 4 raised to the third power, which is the same as 4 * 4 * 4 = 64.

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Your solution:

In (2^4) * 3, we must first evaluate equation in parentheses. (2^4) = 16.

Then, 16 * 3 = 48.

In 2 ^ (4 * 3), we must first evaluate equation in parentheses. (4 * 3) = 12.

Then, 2 ^ 12 = 4096.

confidence rating #$&*:

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3

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Given Solution:

To evaluate (2^4) * 3 we first evaluate the grouped expression 2^4, which is the fourth power of 2, equal to 2 * 2 * 2 * 2 = 16. So we have

(2^4) * 3 = 16 * 3 = 48.

To evaluate 2^(4 * 3) we first do the operation inside the parentheses, obtaining 4 * 3 = 12. We therefore get

2^(4 * 3) = 2^12 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 = 4096.

It is easy to multiply by 2, and the powers of 2 are important, so it's appropriate to have asked you to do this problem without using a calculator. Had the exponent been much higher, or had the calculation been, say, 3^12, the calculation would have become tedious and error-prone, and the calculator would have been recommended.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q006. Calculate 3 * 5 - 4 * 3 ^ 2 and 3 * 5 - (4 * 3)^2 according to the standard order of operations, indicating the order of your steps. Explain, as best you can, the reasons for the difference in your results.

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Your solution:

3 * 5 - 4 * (3^2). According to standard order of operations, we begin with exponents. (3^2) = 9. Left with 3 * 5 - 4 * 9.

Next is multiplication, left to right. 3 * 5 = 15. 4 * 9 = 36. 15 - 36.

Finally, 15 - 36 = -21.

3 * 5 - (4 * 3)^2. We begin with Parentheses. (4 * 3) = 12. Left with 3 * 5 - 12^2.

Next, exponents. 12^2 = 144. 3 * 5 - 144.

Next, multiplication. 3 * 5 = 15. 15 - 144.

Lastly, 15 - 144 = -129.

confidence rating #$&*:

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3

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Given Solution:

To calculate 3 * 5 - 4 * 3 ^ 2, the first operation is the exponentiation operation ^.

The two numbers involved in the exponentiation are 3 and 2; the 4 is 'attached' to the 3 by multiplication, and this multiplication can't be done until the exponentiation has been performed.

The exponentiation operation is therefore 3^2 = 9, and the expression becomes 3 * 5 - 4 * 9.

Evaluating this expression, the multiplications 3 * 5 and 4 * 9 must be performed before the subtraction. 3 * 5 = 15 and 4 * 9 = 36 so we now have

3 * 5 - 4 * 3 ^ 2 = 3 * 5 - 4 * 9 = 15 - 36 = -21.

To calculate 3 * 5 - (4 * 3)^2 we first do the operation in parentheses, obtaining 4 * 3 = 12. Then we apply the exponentiation to get 12 ^2 = 144. Finally we multiply 3 * 5 to get 15. Putting this all together we get

3 * 5 - (4 * 3)^2 =

3 * 5 - 12^2 =

3 * 5 - 144 =

15 - 144 =

-129.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

In the next three problems, the graphs will be of one of the basic shapes listed below. You will be asked to construct graphs for three simple functions, and determine which of the depicted graphs each of your graphs most closely resembles. At this point you won't be expected to know these terms or these graph shapes; if at some point in your course you are expected to know these things, they will be presented at that point.

Linear:

Quadratic or parabolic:

Exponential:

Odd power:

Fractional positive power:

Even negative power:

partial graph of polynomial of degree 3

more extensive graph of polynomial of degree 3

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Question: `q007. Let y = 2 x + 3. (Note: Liberal Arts Mathematics students are encouraged to do this problem, but are not required to do it).

Evaluate y for x = -2. What is your result? In your solution explain the steps you took to get this result.

Evaluate y for x values -1, 0, 1 and 2. Write out a copy of the table below. In your solution give the y values you obtained in your table.

x y

-2

-1

0

1

2

Sketch a graph of y vs. x on a set of coordinate axes resembling the one shown below. You may of course adjust the scale of the x or the y axis to best depict the shape of your graph.

In your solution, describe your graph in words, and indicate which of the graphs depicted previously your graph most resembles. Explain why you chose the graph you did.

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Your solution:

y = 2x + 3

x = -2. y = 2(-2) + 3 = -4 + 3 = -1.

x y

-2 -1

-1 1

0 3

1 5

2 7

My graph has x values -3 through 3, with a scale of 1. The y axes has values -3 through 9, with a scale of 2.

Graphing these points, we find a straight line with slope 2.

A graph with one simple straight line is a 'linear' graph.

confidence rating #$&*:

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3

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Given Solution:

Two slightly different explanations are give below, one by a student and one by the instructor. Neither format is inherently better than the other.

GOOD SOLUTION BY STUDENT:

First we need to complete the table. I have added a column to the right of the table to show the calculation of “y” when we us the “x” values as given.

x y Calculation: If y = 2x + 3

-2 -1 If x = -2, then y = 2(-2)+3 = -4+3 = -1

-1 1 If x= -1, then y = 2(-1)+3 = -2+3 = 1

0 3 If x= 0, then y = 2(0)+3 = 0+3 = 3

1 5 If x= 1, then y = 2(1)+3 = 2+3 = 5

2 7 If x= 2, then y = 2(2)+3 = 4+3 = 7

Once an answer has been determined, the “y” value can be filled in. Now we have both the “x” and “y” values and we can begin our graph. The charted values continue on a straight line representing a linear function as shown above.

INSTRUCTOR'S SOLUTION:

We easily evaluate the expression:

When x = -2, we get y = 2 x + 3 = 2 * (-2) + 3 = -4 + 3 = -1.

When x = -1, we get y = 2 x + 3 = 2 * (-1) + 3 = -2 + 3 = 1.

When x = 0, we get y = 2 x + 3 = 2 * (0) + 3 = 0 + 3 = 3.

When x = 1, we get y = 2 x + 3 = 2 * (1) + 3 = 2 + 3 = 5.

When x = 2, we get y = 2 x + 3 = 2 * (2) + 3 = 4 + 3 = 7.

Filling in the table we have

x y

-2 -1

-1 1

0 3

1 5

2 7

When we graph these points we find that they lie along a straight line.

Only one of the depicted graphs consists of a straight line, and we conclude that the appropriate graph is the one labeled 'linear'.

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Self-critique (if necessary):

I simply showed the math when solving for y with the given x, whereas the given solution uses wording such as 'if,' 'when,' and 'then.'

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Self-critique Rating:

3

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Question: `q008. Let y = x^2 + 3. (Note: Liberal Arts Mathematics students are encouraged to do this problem, but are not required to do it).

Evaluate y for x = -2. What is your result? In your solution explain the steps you took to get this result.

Evaluate y for x values -1, 0, 1 and 2. Write out a copy of the table below. In your solution give the y values you obtained in your table.

x y

-2

-1

0

1

2

Sketch a graph of y vs. x on a set of coordinate axes resembling the one shown below. You may of course adjust the scale of the x or the y axis to best depict the shape of your graph.

In your solution, describe your graph in words, and indicate which of the graphs depicted previously your graph most resembles. Explain why you chose the graph you did.

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Your solution:

When x = - 2, y = (-2)^2 + 3 = 4 + 3 = 7.

x y

-2 7

-1 4

0 3

1 4

2 7

The graph has a curve opening toward the positive y axis and the y-intercept at y = 3.

A graph with this type of curve is quadratic.

confidence rating #$&*:

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3

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Given Solution:

Evaluating y = x^2 + 3 at the five points:

If x = -2 then we obtain y = x^2 + 3 = (-2)^2 + 3 = 4 + 3 = 7.

If x = -1 then we obtain y = x^2 + 3 = (-1)^2 + 3 = ` + 3 = 4.

If x = 0 then we obtain y = x^2 + 3 = (0)^2 + 3 = 0 + 3 = 3.

If x = 1 then we obtain y = x^2 + 3 = (1)^2 + 3 = 1 + 3 = 4.

If x = 2 then we obtain y = x^2 + 3 = (2)^2 + 3 = 4 + 3 = 7.

The table becomes

x y

-2 7

-1 4

0 3

1 4

2 7

We note that there is a symmetry to the y values. The lowest y value is 3, and whether we move up or down the y column from the value 3, we find the same numbers (i.e., if we move 1 space up from the value 3 the y value is 4, and if we move one space down we again encounter 4; if we move two spaces in either direction from the value 3, we find the value 7).

A graph of y vs. x has its lowest point at (0, 3).

If we move from this point, 1 unit to the right our graph rises 1 unit, to (1, 4), and if we move 1 unit to the left of our 'low point' the graph rises 1 unit, to (-1, 4).

If we move 2 units to the right or the left from our 'low point', the graph rises 4 units, to (2, 7) on the right, and to (-2, 7) on the left.

Thus as we move from our 'low point' the graph rises up, becoming increasingly steep, and the behavior is the same whether we move to the left or right of our 'low point'. This reflects the symmetry we observed in the table. So our graph will have a right-left symmetry.

Two of the depicted graphs curve upward away from the 'low point'. One is the graph labeled 'quadratic or parabolic'. The other is the graph labeled 'partial graph of degree 3 polynomial'.

If we look closely at these graphs, we find that only the first has the right-left symmetry, so the appropriate graph is the 'quadratic or parabolic' graph.

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Self-critique (if necessary):

I did not describe the graph as well as the given solution, but simply gave a vague description of what the graph looked like.

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Self-critique Rating:

3

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Question: `q009. Let y = 2 ^ x + 3. (Note: Liberal Arts Mathematics students are encouraged to do this problem, but are not required to do it).

Evaluate y for x = 1. What is your result? In your solution explain the steps you took to get this result.

Evaluate y for x values 2, 3 and 4. Write out a copy of the table below. In your solution give the y values you obtained in your table.

x y

1

2

3

4

Sketch a graph of y vs. x on a set of coordinate axes resembling the one shown below. You may of course adjust the scale of the x or the y axis to best depict the shape of your graph.

In your solution, describe your graph in words, and indicate which of the graphs depicted previously your graph most resembles. Explain why you chose the graph you did.

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Your solution:

When x = 1, y = 2^(1) + 3 = 2 + 3 = 5.

x y

1 5

2 7

3 11

4 19

We see as the x increases, the slope of the line gets steeper because the increase of y gets steadily larger.

This type of graph is defined as an 'exponential' graph because of the curvature as x increases.

confidence rating #$&*:

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3

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Given Solution:

Recall that the exponentiation in the expression 2^x + 1 must be done before, not after the addition.

When x = 1 we obtain y = 2^1 + 3 = 2 + 3 = 5.

When x = 2 we obtain y = 2^2 + 3 = 4 + 3 = 7.

When x = 3 we obtain y = 2^3 + 3 = 8 + 3 = 11.

When x = 4 we obtain y = 2^4 + 3 = 16 + 3 = 19.

x y

1 5

2 7

3 11

4 19

Looking at the numbers in the y column we see that they increase as we go down the column, and that the increases get progressively larger. In fact if we look carefully we see that each increase is double the one before it, with increases of 2, then 4, then 8.

When we graph these points we find that the graph rises as we go from left to right, and that it rises faster and faster. From our observations on the table we know that the graph in fact that the rise of the graph doubles with each step we take to the right.

The only graph that increases from left to right, getting steeper and steeper with each step, is the graph labeled 'exponential'.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q010. If you divide a certain positive number by 1, is the result greater than the original number, less than the original number or equal to the original number, or does the answer to this question depend on the original number?

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Your solution:

As a general rule, any number divided by one will have a result equal to the original number.

Therefore, any positive number divided by one will have a result equal to the original.

confidence rating #$&*:

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3

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Given Solution: If you divide any number by 1, the result is the same as the original number. Doesn't matter what the original number is, if you divide it by 1, you don't change it.

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Self-critique (if necessary):

OK

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Self-critique Rating:

OK

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Question: `q011. If you divide a certain positive number by a number greater than 1, is the result greater than the original number, less than the original number or equal to the original number, or does the answer to this question depend on the original number?

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Your solution:

Given: x = 18.

If x is divided by 2, the result is 9.

If x is divided by 3, the result is 6.

If x is divided by 4, the result is 4.5.

We can see that as the divisor increases, the result decreases. Therefore, no divisor greater than one will ever have a result larger or equal to the original.

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

OK

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Given Solution: If you split something up into equal parts, the more parts you have, the less will be in each one. Dividing a positive number by another number is similar. The bigger the number you divide by, the less you get.

Now if you divide a positive number by 1, the result is the same as your original number. So if you divide the positive number by a number greater than 1, what you get has to be smaller than the original number. Again it doesn't matter what the original number is, as long as it's positive.

Students will often reason from examples. For instance, the following reasoning might be offered:

OK, let's say the original number is 36. Let's divide 36 be a few numbers and see what happens:

36/2 = 18. Now 3 is bigger than 2, and

36 / 3 = 12. The quotient got smaller. Now 4 is bigger than 3, and

36 / 4 = 9. The quotient got smaller again. Let's skip 5 because it doesn't divide evenly into 36.

36 / 6 = 4. Again we divided by a larger number and the quotient was smaller.

I'm convinced.

That is a pretty convincing argument, mainly because it is so consistent with our previous experience. In that sense it's a good argument. It's also useful, giving us a concrete example of how dividing by bigger and bigger numbers gives us smaller and smaller results.

However specific examples, however convincing and however useful, don't actually prove anything. The argument given at the beginning of this solution is general, and applies to all positive numbers, not just the specific positive number chosen here.

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Self-critique (if necessary):

I got the general idea and began the right way, but did not complete the argument in a fulfilling manner.

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Self-critique Rating:

3

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Question: `q012. If you divide a certain positive number by a positive number less than 1, is the result greater than the original number, less than the original number or equal to the original number, or does the answer to this question depend on the original number?

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Your solution:

Any number less than one can be described using a fraction. For example. . 9 = 9/10. If a number is divided by a fraction, we know that we must reciprocate the

fraction and then multiply and divide. With any fraction less than one, the denominator will be greater than the numerator. If the original number is

multiplied by a larger number than its divisor, the result must be greater than the orignal.

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

3

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Given Solution: If you split something up into equal parts, the more parts you have, the less will be in each one. Dividing a positive number by some other number is similar. The bigger the number you divide by, the less you get. The smaller the number you divide by, the more you get.

Now if you divide a positive number by 1, the result is the same as your original number. So if you divide the positive number by a positive number less than 1, what you get has to be larger than the original number. Again it doesn't matter what the original number is, as long as it's positive.

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Self-critique (if necessary):

OK

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Self-critique Rating:

3

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Question: `q013. Students often get the basic answers to nearly all, or even all these questions, correct. Your instructor has however never seen anyone who addressed all the subtleties in the given solutions in their self-critiques, and it is very common for a student to have given no self-critiques. It is very likely that there is something in the given solutions that is not expressed in your solution.

This doesn't mean that you did a bad job. If you got most of the 'answers' right, you did fine.

However, in order to better understand the process, you are asked here to go back and find something in one of the given solutions that you did not address in your solution, and insert a self-critique. You should choose something that isn't trivial to you--something you're not 100% sure you understand.

If you can't find anything, you can indicate this below, and the instructor will point out something and request a response (the instructor will select something reasonable, but will then expect a very good and complete response). However it will probably be less work for you if you find something yourself.

Your response should be inserted at the appropriate place in this document, and should be indicated by preceding it with ####.

As an answer to this question, include a copy of whatever you inserted above, or an indication that you can't find anything.

On question 4, I did not specify that I was deriving my basic knowledge of which operations to do first from the Order of Operations."

Self-critique (if necessary):

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Self-critique rating:

3

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Question: `q013. Students often get the basic answers to nearly all, or even all these questions, correct. Your instructor has however never seen anyone who addressed all the subtleties in the given solutions in their self-critiques, and it is very common for a student to have given no self-critiques. It is very likely that there is something in the given solutions that is not expressed in your solution.

This doesn't mean that you did a bad job. If you got most of the 'answers' right, you did fine.

However, in order to better understand the process, you are asked here to go back and find something in one of the given solutions that you did not address in your solution, and insert a self-critique. You should choose something that isn't trivial to you--something you're not 100% sure you understand.

If you can't find anything, you can indicate this below, and the instructor will point out something and request a response (the instructor will select something reasonable, but will then expect a very good and complete response). However it will probably be less work for you if you find something yourself.

Your response should be inserted at the appropriate place in this document, and should be indicated by preceding it with ####.

As an answer to this question, include a copy of whatever you inserted above, or an indication that you can't find anything.

On question 4, I did not specify that I was deriving my basic knowledge of which operations to do first from the Order of Operations."

Self-critique (if necessary):

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Self-critique rating:

#*&!

&#Your work looks good. Let me know if you have any questions. &#