#$&*
Phy 241
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = 2m/.64s = 3.13m/s
vAve = (v0+vf)/2 ; vf = 2vAve - v0 = 2*3.13m/s -0 = 6.26m/s
`dv = vf-v0 = 6.26m/s-0m/s = 6.26m/s
aAve = `dv/`dt = 6.26m/s / .64s = 9.78m/s^2
#$&*
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve = 5m/1.05s = 4.76m/s
vf = 2*4.76m/s = 9.52m/s
`dv = 9.52m/s
aAve = 9.52m/s / 1.05s = 9.07m/s^2
So this is fairly consistent.
#$&*
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
The first measurement is much more consistent but the second is a little more off.
#$&*
** **
about 5 minutes
** **
&#This looks very good. Let me know if you have any questions. &#