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Phy 241
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
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• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
The motion is in the -x+y quatrant while the force is on the -y axis so the force component that affects the motion would be backwards.
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• Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
Since the force is opposed to the direction of motion, the object would slow down.
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• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
The object is closer to the force when turning left meaning the perpendicular force component vector will be to the left.
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• Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
Since the vector is to the left the object will veer left.
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• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
The combination of the two vectors is 150. The resultant vector is 30 from the motion vector at 120 and 60 from the component perpendicular to the motion at 210. Since the resultant vector is closer to the original motion, the component is along the line of motion.
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about 7 minutes
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&#Very good responses. Let me know if you have questions. &#