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Phy 241
Your 'cq_1_26.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A simple pendulum has length 2 meters. It is pulled back 10 cm from its equilibrium position and released. The tension in the string is 5 Newtons.
• Sketch the system with the pendulum mass at the origin and the x axis horizontal.
answer/question/discussion: ->->->->->->->->->->->-> :
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• Sketch a vector representing the direction of the pendulum string at this instant. As measured from a horizontal x axis, what is the direction of this vector? (Hint: The y component of this vector is practically the same as the length; you are given distance of the pullback in the x direction. So you know the x and y components of the vector.)
answer/question/discussion: ->->->->->->->->->->->-> :
angle=arctan(2m/-.1m)=-87.14+180=92.86
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• What is the direction of the tension force exerted on the mass?
answer/question/discussion: ->->->->->->->->->->->-> :
The force is at 92.86 degrees from the origin and is 5N in magnitude.
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• What therefore are the horizontal and vertical components of the tension?
answer/question/discussion: ->->->->->->->->->->->-> :
x=5Ncos(92.86)=-.25N ; y=5Nsin(92.86)=4.99N
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• What therefore is the weight of the pendulum, and what it its mass?
answer/question/discussion: ->->->->->->->->->->->-> :
m=F/a=4.99N/9.8m/s^2=.51kg
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• What is its acceleration at this instant?
answer/question/discussion: ->->->->->->->->->->->-> :
a=F/m=-.25N/.51=-.49m/s^2
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&#This looks very good. Let me know if you have any questions. &#