phy 201
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity? Avg velocity = change in position / change in time
answer/question/discussion: avg velocity = 30cm/5sec = 6cm/sec
If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: since you are given initial velocity and found avg velocity you can multiply the avg. velocity by 2 to get final
Final velocity = 2 * 6cm/sec = 12cm/sec
By how much did its velocity therefore change?
answer/question/discussion: use the starting and final velocities to find how much the velocity changed = 12cm/sec - 0cm/sec = 12cm/sec
At what average rate did its velocity change with respect to clock time?
answer/question/discussion: since you have the final velocity you can plug that into a rate equation of change in a / change in b
12cm/sec / 5 sec = 2.4 cm/sec
What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: it wouldn’t be a very sharp slope to the right and increasing steadily to the right
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15min
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&#Your work looks very good. Let me know if you have any questions. &#