phy
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion:
Sketch a straight line segment between these points.
answer/question/discussion: the line increases to the right
What are the rise, run and slope of this segment?
answer/question/discussion: rise (velocity) = 40 - 10 = 30 cm
Run (time) = 9 - 4 = 5 sec
Slope (acceleration) = 30/5 = 6 cm /sec
What is the area of the graph beneath this segment?
answer/question/discussion: The area beneath this segment represents the change in position
You can not find the actual area because you need the avg velocity which can only be found if you have final, initial, or constant velocity starting from vO
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30min
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I am unsure about my answer to the last problem. I sketched my graph and I assumed the midpoint or avg velocity was 25 however as it appears in your notes you have to be given a constant velocity or final/initial was i right that avg velocity therefore displacement could not be found due to this?
The average velocity would be 25 cm/s, as you say. So you're very close.
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#