phy 201
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion:
vAve = 10m/8 = 1.25m/s slope = .05in
vAve 2 = 10/5 = 2m/s slope = .10in
1.25m/s/.05 = 25
2m/s/.10 = 20
25-20 = 5m/s change with increase in slope
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15min
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you need to revise this by calculating and using accelerations, which are very different from average velocities
&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
This link also expands on these topics and alerts you to many of the common errors made by students in the first part of this course. &#