course phy 201 if an answer is already in deg/sec should we keep it in this form? I encountered problems where it stated to use radians instead of degrees....Im confused. Ò{ѶŐ×vLyassignment #030
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22:55:26 `q001. Note that this assignment contains 4 questions. If an object rotates through an angle of 20 degrees in five seconds, then at what rate is angle changing?
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RESPONSE --> Find angular velocity omega = dtheta /dt piradian = 180 1 radian = 57.3 xpi57.3= 20 or 20/180 theta = .11 = 1/9 = 1pi/9radians omega = 1pi/9radians / 5sec omega = .2pi/9radians confidence assessment: 2
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23:08:49 The change of 20 degrees in 5 seconds implies a rate of change of 20 degrees / (5 seconds) = 4 deg / sec. We call this the angular velocity of the object, and we designate angular velocity by the symbol `omega.
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RESPONSE --> .2piradians = .2 * 3.14 / 9 * 57.3 = 4 coincidence? The alternate method is much easier. 20deg/5 sec = 4deg/sec self critique assessment: 2
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23:10:08 `q002. What is the average angular velocity of an object which rotates through an angle of 10 `pi radians in 2 seconds?
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RESPONSE --> v = omega * r v = 10piradians / 2 sec v = 5pi radians confidence assessment: 2
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23:10:51 The average angular velocity is equal to the angular displacement divided by the time required for that displacement, in this case giving us `omega = `d`theta / `dt = 10 `pi radians / 2 seconds = 5 `pi rad/s.
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RESPONSE --> self critique assessment:
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23:15:52 `q003. If an object begins with an angular velocity of 3 radians / sec and ends up 10 seconds later within angular velocity of 8 radians / sec, and if the angular velocity changes at a constant rate, then what is the average angular velocity of the object? In this case through how many radians this the object rotate and at what average rate does the angular velocity change?
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RESPONSE --> v0 = 3 rad/sec dt = 10 sec vf=8rad/sec vave = 3 + 8 /2 = 5.5rad/sec 5.5rad * 10 sec = 55 radians dv = 8-3 /10 dv = 5/10 = .5 radians/sec confidence assessment: 2
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23:17:50 Starting at 3 rad/s and ending up at 8 rad/s, the average angular velocity would be expected to be greater than the minimum 3 rad/s and less than the maximum 8 rad/s. If the angular velocity changes at a constant rate, we would in fact expect the average angular velocity to lie halfway between 3 rad/s and 8 rad/s, at the average value (8 rad/s + 3 rad/s) / 2 = 5.5 rad/s. Moving at this average angular velocity for 10 sec the object would rotate through 5.5 rad/s * 10 s = 55 rad in 10 sec. The change in the angular velocity during this 10 seconds is (8 rad/s - 3 rad/s) = 5 rad/s; this change takes place in 10 seconds so that the average rate at which the angular velocity changes must be ( 5 rad / sec ) / (10 sec) = .5 rad/s^2. This is called the average angular acceleration. Angular acceleration is designated by the symbol `alpha. Since the angular velocity in this example changes at a constant rate, the angular acceleration is constant and we therefore say that `alpha = `d `omega / `dt. Again in this case `d`omega is the 5 rad/sec change in the angular velocity.
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RESPONSE --> Being consistant with the original uniform acceler. equartion, these newer equations are easy to remember. self critique assessment: 2
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23:22:40 `q004. If an object starts out with angular velocity 14 rad/s and accelerates at a rate of 4 rad/s^2 for 5 seconds, then at what rate is the object rotating after the 5 seconds? Through how many radians will the object rotate during this time?
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RESPONSE --> v = 14rad/sec a = 4rad/s/s dt = 5sec alpha = domega/dt domega = alpha * dt d omega = 4rad/s/s * 5 sec d omega = 20rad/s/s omegf = 20 + 14 = 34rad/s 34rad/s / 5 sec = 6.8radians confidence assessment: 3
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23:27:47 Changing angular velocity at the rate of 4 rad/s^2 for 5 sec the angular velocity will change by (4 rad/s^2) (5s) = 20 rad/s. Since the angular velocity was already 14 rad/s at the beginning of this time period, it will be 14 rad/s + 20 rad/s = 34 rad/s at the end of the time period. The uniform rate of change of angular velocity implies that the average angular velocity is (14 rad/s + 34 rad/s) / 2 = 24 rad/s. An average angular velocity of 24 radians/second, in 5 seconds the object will rotate through an angle `d`theta = (24 rad/s) ( 5 sec) = 120 rad.
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RESPONSE --> v = ds /dt ds = dt * v vave = 14 + 34 / 2 = 24 ds = 5sec * 24 rad/sec ds = 120 rad I know these equations are the same as the initial vel and accel and I should check my work before letting myself get confused by the different symbols and wording of the problems. All problems thus far have the potential to be broken down into our starting equations. self critique assessment: 2
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