#$&*
phy 201
Your 'cq_1_08.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_08.2_labelMessages **
A ball is tossed upward at 15 meters / second from a height of 12 meters above the ground. Assume a uniform downward acceleration of 10 m/s^2 (an approximation within 2% of the 9.8 m/s^2 acceleration of gravity).
How high does it rise and how long does it take to get to its highest point?
answer/question/discussion: ->->->->->->->->->->->-> :
17.625 m , .75 seconds
@&
After 1 second the ball will still be moving upward at 5 m/s. It won't have yet reached its highest point.
So it won't get to its highest point in .75 seconds.
*@
#$&*
How fast is it then going when it hits the ground, and how long after the initial toss does it first strike the ground?
answer/question/discussion: ->->->->->->->->->->->-> :
-5.776 m/s , 2.0776
@&
I don't believe these are right, and can't tell what you did to get these results.
*@
#$&*
At what clock time(s) will the speed of the ball be 5 meters / second?
answer/question/discussion: ->->->->->->->->->->->-> :
1 second and 2
@&
good
*@
#$&*
At what clock time(s) will the ball be 20 meters above the ground?
How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
1.7312, 7.9984 there is also a negative time bit its irrelevant
-258
@&
You don't show the basis for these results.
The ball will have reached its highest point by the 1.73 second mark. The highest point is higher than 20 meters so it will have passed the 20 meter height by that time.
*@
#$&*
*#&!