course Phy 121 †özÞìBÐæ¡àyûœ¿è۱Íçassignment #001
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16:34:07 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> its the square root of the average of the squared deviations confidence assessment: 3
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16:36:39 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> you make a line that goes through all or most of the points on the graph. two people that made two different graphs will each most likely have a different line of best fit, thus having different slopes and vertical intercepts confidence assessment: 3
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16:38:10 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> it determines how fast an object is going and what direction its going in. confidence assessment: 3
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16:38:27 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> ok self critique assessment: 3
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16:41:45 Given average speed and time interval how do you find distance moved?
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RESPONSE --> speed divided by time will give you the distance confidence assessment: 3
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16:42:00 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> ok self critique assessment: 3
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16:42:42 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> distance moved divided by average speed will give you the time interval confidence assessment: 3
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16:42:52 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> ok self critique assessment: 3
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16:44:03 Given time interval and distance moved how do you get average speed?
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RESPONSE --> take distance moved and divide it by time interval to get average speed confidence assessment: 3
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16:44:15 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> ok self critique assessment: 3
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