#$&*
course Phy 121
Ch 1 Problems1.
a. 1.410 x 10^10 years
b. (1.4 x 10^10y)(3.156 x 10^7s/1y)= 4.4 x 10^17s
2.
a. 3 significant figures
b. 4 significant figures
c. 3 significant figures
d. 1 significant figure
e. 2 significant figures
f. 4 significant figures
g. 2 significant figures
3.
a. 1.156 x 10^0
b. 2.18 x 10^1
c. 6.8 x10^-3
d. 2.7636 x 10^1
e. 2.19 x 10^-1
f. 4.44 x 10^2
4.
a. 86,9000
b. 9,100
c. 0.88
d. 476
e. 0.0000362
12.
a. 0.286 m
b. 0.000085 V
c. 0.000760 kg
d. 0.0000000000600 s
e. 0.0000000000000225m
f. 2,500,000,000 volts
13.
a. 1 megavolt (Mvolt)
b. 2 micrometers (um)
c. 6 kilodays (kdays)
d.18 hectobucks (hbucks)
e. 8 nanopieces (npieces)
14. a. Assuming a height of 5 feet 10 inches, then 5'10"" = (70 in) (1m/ 39.37in) = 1.8 m
b. Assuming a weight of 165 lbs, then (165 lbs) (0.456 kg/1lb) = 75.2kg
Technically, pounds and mass measure two separate properties. To make this conversion, we have to assume that we are at a location where the acceleration due to gravity is 9.8 m/s2.
15. a. 93 million miles (93x10^6 miles) (1610 m/1 mile) = 1.5 x 10^11 m
b. 1.5 x 10^11 m = 150 x 10^9 m = 150 gigameters or 1.5 x 10^11 m = 0.15 x 10^12 m = 0.15 terameters
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@& You don't need to submit a list of answers to your problems.
You do need to submit the q_a_ and the Query.
If you have a question on a problem not covered in the Query you can submit your question using the Submit Work Form. I'm always glad to respond to questions submitted in that manner.
I can easily see what you did on the last several problems and you appear to be doing very well here.*@