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Phy 121
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6 cm/sec
@& This is the change in velocity, not the average velocity.*@
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Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Because it is cm/sec and we don't know how much time is pasted and it is a variable. Velocity = the change of distance/the change of time.
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If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that
time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6/3 = 2cm/sec
@& 6 and 3 are quantitie that have units. The units need to be included.
*@
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At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6/3 = 2cm/sec
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@& You didn't include units, and the units are not correct.
However you did divide the ight numbers.*@
*#&!
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&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
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