cq_1_051

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Phy 121

Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

What will be its velocity after the 3 seconds has elapsed?

answer/question/discussion: ->->->->->->->->->->->-> :

The velocity would be 8cm/s^2 * 3sec = 24cm/s for be the velocity after the 3 seconds elapses.

@& This would be the change in velocity.*@

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Assuming that acceleration is constant, what will be its average velocity during this interval?

answer/question/discussion: ->->->->->->->->->->->-> :

(12cm/s + 24cm/s)/2 = 18cm/s would be the average velocity during this interval.

@& Right idea, but it turns out that you're averaging the initial velocity and the change in velocity, not the initial velocity and the final velocity.*@

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How far will it travel during this interval?

answer/question/discussion: ->->->->->->->->->->->-> :

(12cm/s + 24cm/s)/2 * 3sec = 24cm will be the distanced traveled.

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*#&!*#&!*#&!

@& You're on the right track, but you didn't get the correct final velocity.

No need for a revision unless you don't understand the discussion, but to check out the link:

&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your old and new solutions with the expanded discussion at the link

Solution

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If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#