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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
a = 8 cm/s^2
t = 3 sec
v 0 = 12 cm/s
v = 12 cm/s + (8 cm/s^2) (3 s)
= 12 cm/s + 24 cm/s
= 36 cm/s
• Assuming that acceleration is constant, what will be its average velocity during this interval?
vAve = (36 cm/s + 12 cm/s) / 2 = 24 cm/s
• How far will it travel during this interval?
`ds = 36 – 12 = 24 cm/s * 3 sec = 72 cm
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20 min
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&#This looks very good. Let me know if you have any questions. &#