course Phy 201 MèÀÁÏÛÄí„И剃‹À xpÇÇ«¡ŒI¬¯…Û~assignment #004
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22:21:03 Intro Prob 6 given init vel, accel, `dt find final vel, dist If initial velocity is v0, acceleration is a and time interval is `dt, then in symbols what are the final velocity vf and the displacement `ds?
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RESPONSE --> vf is final velocity and `ds is change in displacement. confidence assessment: 2
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22:24:31 **You would use accel. and `dt to find `dv: a * `dt = `dv. Adding `dv to initial vel. vo you get final vel. Then average initial vel. and final vel. to get ave. vel.: (v0 + vf) / 2 = ave. vel. You would then multiply ave. vel. and `dt together to get the distance. For example if a = 3 m/s^2, `dt = 5 s and v0 = 3 m/s: 3 m/s^2 * 5 s = 15 m/s = `dv 15 m/s + 3 m/s = 18 m/s = fin. vel. (18 m/s + 3 m/s) / 2 = 10.5 m/s = vAve 10.5 m/s * 5 s = 52.5 m = dist. In more abbreviated form: a * `dt = `dv v0 + `dv = vf (vf + v0) /2 = vAve vAve * `dt = `ds so `ds = (vf + v0) / 2 * `dt. **
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RESPONSE --> I misunderstood the question. This example was very helpful in understanding the equations. self critique assessment: 2
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22:26:34 What is the displacement `ds associated with uniform acceleration from velocity v0 to velocity vf in clock time `dt?
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RESPONSE --> Final velocity and initial velocity are necessary to find the average velocity. Once you have the average velocity you can then multiply that by the change in time to obtain the displacement or `ds. confidence assessment: 2
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22:26:46 ** Since accel is uniform vAve = (v0 + vf) / 2. Thus displacement is `ds = vAve * `dt = (v0 + vf) / 2 * `dt, which is the first equation of uniformly accelerated motion. **
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RESPONSE --> ok self critique assessment: 3
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22:28:55 Describe the flow diagram we obtain for the situation in which we know v0, vf and `dt.
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RESPONSE --> The flow diagram would show that final velocity minus initial velocity would give us change in velocity which would then be divided by average velocity to get the change in time. confidence assessment: 2
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22:32:06 ** The first level in the diagram would contain `dt, v0 and vf. Then v0 and vf would connect to `dv in the second level. The second level would also contain vAve, connected from vf in the first level to v0 in the first level. The third level would contain an a, connected to `dv in the second level and `dt in the first level. The third level would also contain `ds, connected to vAve in the fourth level and `dt in the first level. **
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RESPONSE --> ok self critique assessment: 2
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22:32:55 Query Add any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> I misunderstood the first question. This query was helpful by providing more examples to help me think through the problems more. confidence assessment: 2
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22:33:17 ** Student Response: I think I really confused what information stood for what in the Force and Pendulum Experiment. However, I enjoy doing the flow diagrams. They make you think in a different way than you are used to. INSTRUCTOR NOTE: These diagrams are valuable for most people. Not all--it depends on learning style--but most. **
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RESPONSE --> ok self critique assessment: 2
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